{"id":256119,"date":"2025-07-14T04:03:28","date_gmt":"2025-07-14T04:03:28","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=256119"},"modified":"2025-07-14T04:03:31","modified_gmt":"2025-07-14T04:03:31","slug":"there-are-three-known-compounds-with-the-molecular-formula-of-c2h2cl2-but-only-one-with-the-formula-of-c2h3cl","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/07\/14\/there-are-three-known-compounds-with-the-molecular-formula-of-c2h2cl2-but-only-one-with-the-formula-of-c2h3cl\/","title":{"rendered":"There are three known compounds with the molecular formula of C2H2Cl2 but only one with the formula of C2H3Cl."},"content":{"rendered":"\n<p>There are three known compounds with the molecular formula of C2H2Cl2 but only one with the formula of C2H3Cl. Explain this in terms of molecular structure by drawing the four structures, identify which molecules are polar.<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-0-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>The molecular formula C2H2Cl2 corresponds to three different compounds due to different structural arrangements of atoms. These compounds are <strong>1,1-dichloroethene<\/strong>, <strong>cis-1,2-dichloroethene<\/strong>, and <strong>trans-1,2-dichloroethene<\/strong>. Similarly, there is only one compound with the formula <strong>C2H3Cl<\/strong>, which is <strong>chloroethene (vinyl chloride)<\/strong>.<\/p>\n\n\n\n<p>Let&#8217;s break down the structures and their polarity:<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">1. <strong>1,1-Dichloroethene<\/strong>:<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Structure: Cl-CH=CH-Cl.<\/li>\n\n\n\n<li>In this structure, both chlorine atoms are attached to the same carbon atom.<\/li>\n\n\n\n<li>The molecule is <strong>polar<\/strong> because of the presence of two chlorine atoms on the same carbon, creating a dipole moment in the direction of the chlorine atoms.<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\">2. <strong>Cis-1,2-Dichloroethene<\/strong>:<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Structure: Cl-CH=CH-Cl (with both chlorines on the same side).<\/li>\n\n\n\n<li>This molecule has a <strong>polar<\/strong> structure due to the difference in electronegativity between the carbon-hydrogen bonds and the chlorine atoms, creating a dipole along the axis of the molecule.<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\">3. <strong>Trans-1,2-Dichloroethene<\/strong>:<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Structure: Cl-CH=CH-Cl (with chlorines on opposite sides).<\/li>\n\n\n\n<li>Despite having the same atoms, this molecule is <strong>non-polar<\/strong>. The dipoles cancel each other out because of the symmetry of the trans arrangement.<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\">4. <strong>Chloroethene (C2H3Cl)<\/strong>:<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Structure: CH2=CH-Cl.<\/li>\n\n\n\n<li>This molecule is <strong>polar<\/strong> because the chlorine atom is more electronegative than carbon, creating a dipole moment.<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\">Polarity Summary:<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>1,1-Dichloroethene<\/strong>: Polar.<\/li>\n\n\n\n<li><strong>Cis-1,2-Dichloroethene<\/strong>: Polar.<\/li>\n\n\n\n<li><strong>Trans-1,2-Dichloroethene<\/strong>: Non-polar.<\/li>\n\n\n\n<li><strong>Chloroethene<\/strong>: Polar.<\/li>\n<\/ul>\n\n\n\n<p>The reason there is only one compound with the formula <strong>C2H3Cl<\/strong> is that the structure can only be <strong>chloroethene (vinyl chloride)<\/strong>, where the hydrogen atoms are arranged in a specific way with chlorine.<\/p>\n\n\n\n<p>This explanation highlights the importance of molecular symmetry and electronegativity in determining polarity.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/07\/learnexams-banner6-573.jpeg\" alt=\"\" class=\"wp-image-256120\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>There are three known compounds with the molecular formula of C2H2Cl2 but only one with the formula of C2H3Cl. Explain this in terms of molecular structure by drawing the four structures, identify which molecules are polar. The Correct Answer and Explanation is: The molecular formula C2H2Cl2 corresponds to three different compounds due to different structural [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-256119","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/256119","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=256119"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/256119\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=256119"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=256119"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=256119"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}