{"id":256210,"date":"2025-07-15T19:51:20","date_gmt":"2025-07-15T19:51:20","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=256210"},"modified":"2025-07-15T19:51:26","modified_gmt":"2025-07-15T19:51:26","slug":"which-is-the-correct-order-of-bond-angle","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/07\/15\/which-is-the-correct-order-of-bond-angle\/","title":{"rendered":"Which is the correct order of bond angle"},"content":{"rendered":"\n

Which is the correct order of bond angle? A. Cl – P – Cl in, PCl3F2 > Cl – As – Cl in AsCl3F2 B. F – P – Cl in, PCl3F2 > F – As – Cl in AsCl3F2 C. F – P – F in, PCl3F2 < F – As – F in AsCl3F2 D. Cl – P – Cl in, PCl3F2 = Cl – As – Cl in AsCl3F2<\/p>\n\n\n\n

The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n

Correct answer: B. F – P – Cl in PCl3F2 > F – As – Cl in AsCl3F2<\/strong><\/p>\n\n\n\n

Explanation:<\/h3>\n\n\n\n

The bond angle in a molecule depends on several factors, such as the central atom\u2019s size, electronegativity, hybridization, and the repulsion between bonding and nonbonding electron pairs.<\/p>\n\n\n\n

PCl3F2 and AsCl3F2 are both trigonal bipyramidal<\/strong> in geometry. In such structures, the atoms can occupy either axial<\/strong> or equatorial<\/strong> positions. The bond angles are typically 90 degrees between axial and equatorial positions and 120 degrees between two equatorial positions.<\/p>\n\n\n\n

In both molecules:<\/p>\n\n\n\n

    \n
  • Phosphorus (P)<\/strong> and arsenic (As)<\/strong> are in Group 15.<\/li>\n\n\n\n
  • However, phosphorus is smaller and more electronegative<\/strong> than arsenic.<\/li>\n<\/ul>\n\n\n\n

    Let us now analyze option B:<\/p>\n\n\n\n

      \n
    • In PCl3F2<\/strong>, the F – P – Cl angle involves a more electronegative and smaller central atom (phosphorus).<\/li>\n\n\n\n
    • In AsCl3F2<\/strong>, the same angle is slightly smaller due to the larger size and lower electronegativity of arsenic.<\/li>\n\n\n\n
    • A smaller central atom (like phosphorus)<\/strong> pulls bonded atoms closer together, but due to stronger electron repulsion among highly electronegative ligands (like F and Cl), the angle can be more expanded to minimize repulsion.<\/li>\n\n\n\n
    • As<\/strong>, being larger, allows more spatial flexibility, but its lower electronegativity results in weaker repulsions<\/strong>, which can cause bond angles like F – As – Cl to be slightly less.<\/li>\n<\/ul>\n\n\n\n

      Therefore, F – P – Cl<\/strong> has a greater bond angle<\/strong> than F – As – Cl<\/strong>, making option B the correct answer<\/strong>.<\/p>\n\n\n\n

      Options A, C, and D either incorrectly estimate equality or inverse relationships that do not align with periodic trends and electron repulsion principles.<\/p>\n\n\n\n

      \"\"<\/figure>\n","protected":false},"excerpt":{"rendered":"

      Which is the correct order of bond angle? A. Cl – P – Cl in, PCl3F2 > Cl – As – Cl in AsCl3F2 B. F – P – Cl in, PCl3F2 > F – As – Cl in AsCl3F2 C. F – P – F in, PCl3F2 < F – As – F in […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-256210","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/256210","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=256210"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/256210\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=256210"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=256210"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=256210"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}