{"id":257432,"date":"2025-07-17T11:51:17","date_gmt":"2025-07-17T11:51:17","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=257432"},"modified":"2025-07-17T11:51:20","modified_gmt":"2025-07-17T11:51:20","slug":"draw-the-lewis-structure-for-ocnthe-atoms-are-bonded-in-the-order-given-2","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/07\/17\/draw-the-lewis-structure-for-ocnthe-atoms-are-bonded-in-the-order-given-2\/","title":{"rendered":"Draw the Lewis structure for OCN(the atoms are bonded in the order given)"},"content":{"rendered":"\n<p>Draw the Lewis structure for OCN<br>(the atoms are bonded in the order given). Include all formal charges and resonance structures. Circle which structure would be the MAJOR contributor.<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>To draw the Lewis structure for the OCN\u207b ion (also called the cyanate ion), with atoms bonded in the order <strong>O\u2013C\u2013N<\/strong>, follow these steps:<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Step 1: Count total valence electrons<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Oxygen (O) = 6 valence electrons<\/li>\n\n\n\n<li>Carbon (C) = 4 valence electrons<\/li>\n\n\n\n<li>Nitrogen (N) = 5 valence electrons<\/li>\n\n\n\n<li>Extra electron due to the negative charge = 1 electron<\/li>\n<\/ul>\n\n\n\n<p><strong>Total = 6 + 4 + 5 + 1 = 16 valence electrons<\/strong><\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Step 2: Draw possible resonance structures<\/h3>\n\n\n\n<p>Let\u2019s construct 3 possible resonance structures while maintaining the O\u2013C\u2013N bonding order.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<p><strong>Structure A:<\/strong><\/p>\n\n\n\n<pre class=\"wp-block-preformatted\">mathematicaCopyEdit<code>O=C=N\u207b\n<\/code><\/pre>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Oxygen: double bonded to carbon<\/li>\n\n\n\n<li>Carbon: double bonds with both O and N<\/li>\n\n\n\n<li>Nitrogen: lone pair and negative formal charge<\/li>\n<\/ul>\n\n\n\n<p>Formal charges:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>O: 6 \u2013 (4 non-bonding + 2 bonding) = <strong>0<\/strong><\/li>\n\n\n\n<li>C: 4 \u2013 (0 non-bonding + 4 bonding) = <strong>0<\/strong><\/li>\n\n\n\n<li>N: 5 \u2013 (6 non-bonding + 2 bonding) = <strong>\u20131<\/strong><\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<p><strong>Structure B:<\/strong><\/p>\n\n\n\n<pre class=\"wp-block-preformatted\">mathematicaCopyEdit<code>O\u2013C\u2261N\u207b\n<\/code><\/pre>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Oxygen: single bond to carbon<\/li>\n\n\n\n<li>Carbon: triple bond to nitrogen<\/li>\n\n\n\n<li>Nitrogen: one lone pair, negative charge<\/li>\n<\/ul>\n\n\n\n<p>Formal charges:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>O: 6 \u2013 (6 non-bonding + 1 bonding) = <strong>\u20131<\/strong><\/li>\n\n\n\n<li>C: 4 \u2013 (0 non-bonding + 4 bonding) = <strong>0<\/strong><\/li>\n\n\n\n<li>N: 5 \u2013 (2 non-bonding + 3 bonding) = <strong>0<\/strong><\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<p><strong>Structure C:<\/strong><\/p>\n\n\n\n<pre class=\"wp-block-preformatted\">mathematicaCopyEdit<code>\u207bO\u2261C\u2013N\n<\/code><\/pre>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Oxygen: triple bond to carbon, negative charge<\/li>\n\n\n\n<li>Carbon: single bond to nitrogen<\/li>\n\n\n\n<li>Nitrogen: full octet<\/li>\n<\/ul>\n\n\n\n<p>Formal charges:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>O: 6 \u2013 (2 non-bonding + 3 bonding) = <strong>+1<\/strong><\/li>\n\n\n\n<li>C: 4 \u2013 (0 non-bonding + 4 bonding) = <strong>0<\/strong><\/li>\n\n\n\n<li>N: 5 \u2013 (6 non-bonding + 1 bonding) = <strong>\u20132<\/strong><\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Step 3: Identify the MAJOR contributor<\/h3>\n\n\n\n<p>Structure <strong>B (O\u2013C\u2261N\u207b)<\/strong> is the <strong>major resonance contributor<\/strong> because:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>All atoms follow the octet rule<\/li>\n\n\n\n<li>The negative charge is on oxygen, the most electronegative atom<\/li>\n\n\n\n<li>Formal charges are minimized and more stable<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Final Answer:<\/h3>\n\n\n\n<p>\u2705 <strong>Major resonance structure:<\/strong> O\u2013C\u2261N\u207b<br>Other valid structures: O=C=N\u207b and \u207bO\u2261C\u2013N<\/p>\n\n\n\n<p>This explains electron delocalization and shows the cyanate ion is resonance stabilized.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/07\/learnexams-banner6-767.jpeg\" alt=\"\" class=\"wp-image-257433\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Draw the Lewis structure for OCN(the atoms are bonded in the order given). Include all formal charges and resonance structures. Circle which structure would be the MAJOR contributor. The Correct Answer and Explanation is: To draw the Lewis structure for the OCN\u207b ion (also called the cyanate ion), with atoms bonded in the order O\u2013C\u2013N, [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-257432","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/257432","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=257432"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/257432\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=257432"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=257432"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=257432"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}