{"id":257589,"date":"2025-07-17T14:56:26","date_gmt":"2025-07-17T14:56:26","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=257589"},"modified":"2025-07-17T14:56:28","modified_gmt":"2025-07-17T14:56:28","slug":"choose-the-selection-which-correctly-identifies-the-sets-of-hybrid-orbitals-used-by-central-atoms-to-form-bonds-in-both-of-the-molecules-and-or-ions-whose-formulas-are-given-below","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/07\/17\/choose-the-selection-which-correctly-identifies-the-sets-of-hybrid-orbitals-used-by-central-atoms-to-form-bonds-in-both-of-the-molecules-and-or-ions-whose-formulas-are-given-below\/","title":{"rendered":"Choose the selection which correctly identifies the sets of hybrid orbitals used by central atoms to form bonds in both of the molecules and\/or ions whose formulas are given below"},"content":{"rendered":"\n<p>Choose the selection which correctly identifies the sets of hybrid orbitals used by central atoms to form bonds in both of the molecules and\/or ions whose formulas are given below: CCl3- and IF4- a) The central atom of CCl3- uses sp2 hybridization and the central atom of IF4- uses sp3 hybridization. b) The central atom of CCl3- uses sp3 hybridization and the central atom of IF4- uses sp3d hybridization. c) The central atom of CCl3- uses sp3d hybridization and the central atom of IF4- uses sp3d2 hybridization. d) The central atom of CCl3- uses sp3 hybridization and the central atom of IF4- uses sp3 hybridization. e) The central atom of CCl3- uses sp3 hybridization and the central atom of IF4- uses sp3d2 hybridization.<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-0-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>To determine the hybridization of the central atoms in <strong>CCl3-<\/strong> and <strong>IF4-<\/strong>, we need to analyze the molecular geometry and the number of electron regions (bonds and lone pairs) around each central atom.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">1. <strong>CCl3- (Chloromethyl anion)<\/strong>:<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The central atom is <strong>carbon<\/strong>.<\/li>\n\n\n\n<li>Carbon in CCl3- is surrounded by <strong>three chlorine atoms<\/strong> and one lone pair (due to the negative charge).<\/li>\n\n\n\n<li>This gives a total of <strong>four electron regions<\/strong> (three bonds and one lone pair).<\/li>\n\n\n\n<li>When there are four electron regions around the central atom, the geometry is <strong>tetrahedral<\/strong>, which corresponds to <strong>sp3 hybridization<\/strong>.<\/li>\n\n\n\n<li>Therefore, the central carbon in <strong>CCl3-<\/strong> uses <strong>sp3 hybridization<\/strong>.<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\">2. <strong>IF4- (Tetrafluoroiodate anion)<\/strong>:<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The central atom is <strong>iodine<\/strong>.<\/li>\n\n\n\n<li>Iodine in IF4- is surrounded by <strong>four fluorine atoms<\/strong> and one lone pair (due to the negative charge).<\/li>\n\n\n\n<li>This gives a total of <strong>five electron regions<\/strong> (four bonds and one lone pair).<\/li>\n\n\n\n<li>With five electron regions, the geometry is <strong>trigonal bipyramidal<\/strong>, which corresponds to <strong>sp3d hybridization<\/strong>.<\/li>\n\n\n\n<li>Therefore, the central iodine in <strong>IF4-<\/strong> uses <strong>sp3d hybridization<\/strong>.<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\">Conclusion:<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>CCl3-<\/strong> has <strong>sp3 hybridization<\/strong> on the central carbon.<\/li>\n\n\n\n<li><strong>IF4-<\/strong> has <strong>sp3d hybridization<\/strong> on the central iodine.<\/li>\n<\/ul>\n\n\n\n<p>The correct answer is:<br><strong>b) The central atom of CCl3- uses sp3 hybridization and the central atom of IF4- uses sp3d hybridization.<\/strong><\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation:<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>CCl3-<\/strong> has four electron regions around the central carbon, requiring <strong>sp3 hybridization<\/strong>.<\/li>\n\n\n\n<li><strong>IF4-<\/strong> has five electron regions around the central iodine, requiring <strong>sp3d hybridization<\/strong>.<\/li>\n<\/ul>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/07\/learnexams-banner6-797.jpeg\" alt=\"\" class=\"wp-image-257590\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Choose the selection which correctly identifies the sets of hybrid orbitals used by central atoms to form bonds in both of the molecules and\/or ions whose formulas are given below: CCl3- and IF4- a) The central atom of CCl3- uses sp2 hybridization and the central atom of IF4- uses sp3 hybridization. b) The central atom [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center 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