{"id":257843,"date":"2025-07-17T17:54:18","date_gmt":"2025-07-17T17:54:18","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=257843"},"modified":"2025-07-17T17:54:20","modified_gmt":"2025-07-17T17:54:20","slug":"calculate-the-molar-mass-of-ch4","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/07\/17\/calculate-the-molar-mass-of-ch4\/","title":{"rendered":"Calculate the molar mass of CH4"},"content":{"rendered":"\n

Calculate the molar mass of CH4 (atomic mass: H = 1, C = 12) 12 g\/mol 14 g\/mol 13 g\/mol 16 g\/mol<\/p>\n\n\n\n

The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n

To calculate the molar mass of methane (CH\u2084), we need to sum the atomic masses of all the elements in the molecule.<\/p>\n\n\n\n

Step-by-step calculation:<\/strong><\/p>\n\n\n\n

    \n
  1. Carbon (C):<\/strong>\n
      \n
    • There is 1 carbon atom in CH\u2084, and the atomic mass of carbon is 12 g\/mol.<\/li>\n\n\n\n
    • So, the contribution of carbon to the molar mass is: 1\u00d712\u2009g\/mol=12\u2009g\/mol1 \\times 12 \\, \\text{g\/mol} = 12 \\, \\text{g\/mol}1\u00d712g\/mol=12g\/mol<\/li>\n<\/ul>\n<\/li>\n\n\n\n
    • Hydrogen (H):<\/strong>\n
        \n
      • There are 4 hydrogen atoms in CH\u2084, and the atomic mass of hydrogen is 1 g\/mol.<\/li>\n\n\n\n
      • So, the contribution of hydrogen to the molar mass is: 4\u00d71\u2009g\/mol=4\u2009g\/mol4 \\times 1 \\, \\text{g\/mol} = 4 \\, \\text{g\/mol}4\u00d71g\/mol=4g\/mol<\/li>\n<\/ul>\n<\/li>\n<\/ol>\n\n\n\n

        Total Molar Mass of CH\u2084:<\/strong> 12\u2009g\/mol+4\u2009g\/mol=16\u2009g\/mol12 \\, \\text{g\/mol} + 4 \\, \\text{g\/mol} = 16 \\, \\text{g\/mol}12g\/mol+4g\/mol=16g\/mol<\/p>\n\n\n\n

        So, the correct molar mass of CH\u2084 is 16 g\/mol<\/strong>.<\/p>\n\n\n\n

        Why this is the correct answer:<\/h3>\n\n\n\n

        The molar mass of a molecule is determined by adding the atomic masses of each element it contains. The atomic mass of carbon is 12 g\/mol, and each hydrogen atom contributes 1 g\/mol. By adding the contributions from carbon and hydrogen, we get the total molar mass of CH\u2084 as 16 g\/mol.<\/p>\n\n\n\n

        This is the standard molar mass for methane, which is a common simple molecule and often appears in chemistry calculations, particularly those related to combustion and gas laws.<\/p>\n\n\n\n

        \"\"<\/figure>\n","protected":false},"excerpt":{"rendered":"

        Calculate the molar mass of CH4 (atomic mass: H = 1, C = 12) 12 g\/mol 14 g\/mol 13 g\/mol 16 g\/mol The Correct Answer and Explanation is: To calculate the molar mass of methane (CH\u2084), we need to sum the atomic masses of all the elements in the molecule. Step-by-step calculation: Total Molar Mass […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-257843","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/257843","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=257843"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/257843\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=257843"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=257843"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=257843"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}