How many hybrid orbitals are found in CCl4? <\/p>\n\n\n\n
one<\/p>\n\n\n\n
two <\/p>\n\n\n\n
three <\/p>\n\n\n\n
four<\/p>\n\n\n\n
The correct answer and explanation is:<\/mark><\/strong><\/p>\n\n\n\n The correct answer is four<\/strong>.<\/p>\n\n\n\n In CCl\u2084 (carbon tetrachloride), the central atom is carbon, which is bonded to four chlorine atoms. The carbon atom undergoes sp\u00b3 hybridization<\/strong> to form four equivalent hybrid orbitals. This is because carbon has four valence electrons and needs to form four covalent bonds, one with each chlorine atom.<\/p>\n\n\n\n For the hybridization process to occur, carbon\u2019s 2s orbital combines with its three 2p orbitals, resulting in four equivalent sp\u00b3 hybrid orbitals. Each of these hybrid orbitals will form a sigma bond with the chlorine atoms, using one of the four bonding pairs of electrons. The bond angles in CCl\u2084 are approximately 109.5\u00b0<\/strong>, which is characteristic of tetrahedral geometry, the result of sp\u00b3 hybridization.<\/p>\n\n\n\n The sp\u00b3 hybridization<\/strong> in CCl\u2084 leads to a tetrahedral molecular geometry, and the bond formation is facilitated by the overlap of the carbon’s hybrid orbitals with the chlorine\u2019s p orbitals. The hybrid orbitals on carbon each form a single sigma bond with the 3p orbitals of chlorine, completing the octet on both atoms.<\/p>\n\n\n\n This configuration allows CCl\u2084 to be a stable, non-polar molecule due to the symmetrical distribution of charge. Even though the individual C-Cl bonds are polar, the symmetry of the tetrahedral shape cancels out any dipole moments, resulting in no overall dipole moment for the molecule.<\/p>\n\n\n\n Thus, in CCl\u2084, there are four sp\u00b3 hybrid orbitals<\/strong> formed from the combination of carbon\u2019s s and p orbitals, one of which forms a bond with each chlorine atom.<\/p>\n","protected":false},"excerpt":{"rendered":" How many hybrid orbitals are found in CCl4? one two three four The correct answer and explanation is: The correct answer is four. In CCl\u2084 (carbon tetrachloride), the central atom is carbon, which is bonded to four chlorine atoms. The carbon atom undergoes sp\u00b3 hybridization to form four equivalent hybrid orbitals. This is because carbon […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-258615","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/258615","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=258615"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/258615\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=258615"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=258615"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=258615"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}