Among the pairs listed, H\u2083PO\u2084 and NaH\u2082PO\u2084<\/strong> will form a buffer solution.<\/p>\n\n\n\n A buffer solution<\/strong> is formed when a weak acid is combined with its conjugate base (or a weak base with its conjugate acid). This system resists changes in pH when small amounts of acids or bases are added. The effectiveness of a buffer is determined by the presence of these weak acid\/base pairs, which can neutralize any added acid or base.<\/p>\n\n\n\n Let’s examine the pairs one by one:<\/p>\n\n\n\n In conclusion, the only correct buffer pair is H\u2083PO\u2084 and NaH\u2082PO\u2084<\/strong>.<\/p>\n\n\n\n Which pair of substances will form a buffer solution? HCl; NaCl HNO3; NaNO3 H3PO4, NaH2PO4 H2SO4, CH3COOH NH3, NaOH The Correct Answer and Explanation is: Among the pairs listed, H\u2083PO\u2084 and NaH\u2082PO\u2084 will form a buffer solution. Explanation: A buffer solution is formed when a weak acid is combined with its conjugate base (or a […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-259358","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/259358","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=259358"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/259358\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=259358"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=259358"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=259358"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}Explanation:<\/h3>\n\n\n\n
\n
HCl is a strong acid and NaCl is the salt of a strong acid and strong base. A strong acid like HCl dissociates completely in solution, and NaCl does not provide a conjugate base to neutralize any added acid. Therefore, this pair cannot<\/strong> form a buffer.<\/li>\n\n\n\n
HNO\u2083 is also a strong acid, and NaNO\u2083 is a salt formed from a strong acid (HNO\u2083) and a strong base (NaOH). Similar to HCl, HNO\u2083 dissociates fully in solution, and there is no weak acid\/base pair present. Hence, this pair cannot<\/strong> form a buffer.<\/li>\n\n\n\n
Phosphoric acid (H\u2083PO\u2084) is a weak acid, and NaH\u2082PO\u2084 is its sodium salt, which contains the conjugate base H\u2082PO\u2084\u207b. The presence of both H\u2083PO\u2084 and H\u2082PO\u2084\u207b in solution makes this a buffer pair. The weak acid (H\u2083PO\u2084) can donate protons (H\u207a), and the conjugate base (H\u2082PO\u2084\u207b) can absorb protons, maintaining the pH of the solution. Therefore, this pair can<\/strong> form a buffer.<\/li>\n\n\n\n
H\u2082SO\u2084 is a strong acid, and CH\u2083COOH (acetic acid) is a weak acid. Since H\u2082SO\u2084 dissociates completely, it does not form a conjugate base that can act as a buffer. Therefore, this pair cannot<\/strong> form a buffer.<\/li>\n\n\n\n
NH\u2083 is a weak base and does not have a conjugate acid (in the context of forming a buffer with only NH\u2083 as the species). Hence, a buffer cannot be formed with just NH\u2083.<\/li>\n<\/ol>\n\n\n\n![\"\"](\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/07\/learnexams-banner6-946.jpeg\")
<\/figure>\n","protected":false},"excerpt":{"rendered":"