{"id":259451,"date":"2025-07-19T02:00:52","date_gmt":"2025-07-19T02:00:52","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=259451"},"modified":"2025-07-19T02:00:55","modified_gmt":"2025-07-19T02:00:55","slug":"the-molar-mass-of-cabr2-is-199-89-g-mol","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/07\/19\/the-molar-mass-of-cabr2-is-199-89-g-mol\/","title":{"rendered":"The molar mass of CaBr2 is 199.89 g\/mol"},"content":{"rendered":"\n

The molar mass of CaBr2 is 199.89 g\/mol<\/p>\n\n\n\n

The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n

The molar mass of calcium bromide (CaBr2) is calculated by adding the molar masses of its constituent elements, calcium (Ca) and bromine (Br).<\/p>\n\n\n\n

    \n
  1. Calcium (Ca)<\/strong> has an atomic mass of approximately 40.08 g\/mol<\/strong>.<\/li>\n\n\n\n
  2. Bromine (Br)<\/strong> has an atomic mass of approximately 79.90 g\/mol<\/strong>. Since there are two bromine atoms in CaBr2, we need to multiply this atomic mass by 2.<\/li>\n<\/ol>\n\n\n\n

    Now, let’s calculate the molar mass of CaBr2:Molar mass of CaBr2=(Molar mass of Ca)+2\u00d7(Molar mass of Br)\\text{Molar mass of CaBr2} = \\text{(Molar mass of Ca)} + 2 \\times \\text{(Molar mass of Br)}Molar mass of CaBr2=(Molar mass of Ca)+2\u00d7(Molar mass of Br)Molar mass of CaBr2=40.08\u2009g\/mol+2\u00d779.90\u2009g\/mol\\text{Molar mass of CaBr2} = 40.08 \\, \\text{g\/mol} + 2 \\times 79.90 \\, \\text{g\/mol}Molar mass of CaBr2=40.08g\/mol+2\u00d779.90g\/molMolar mass of CaBr2=40.08\u2009g\/mol+159.80\u2009g\/mol\\text{Molar mass of CaBr2} = 40.08 \\, \\text{g\/mol} + 159.80 \\, \\text{g\/mol}Molar mass of CaBr2=40.08g\/mol+159.80g\/molMolar mass of CaBr2=199.88\u2009g\/mol\\text{Molar mass of CaBr2} = 199.88 \\, \\text{g\/mol}Molar mass of CaBr2=199.88g\/mol<\/p>\n\n\n\n

    So, the molar mass of CaBr2 is 199.88 g\/mol<\/strong>, which rounds to 199.89 g\/mol<\/strong> depending on the level of precision used.<\/p>\n\n\n\n

    This calculation is fundamental in stoichiometric calculations, where the molar mass helps determine the amount of substance in moles from a given mass or vice versa. The molar mass is also crucial in chemical reactions for balancing equations and determining limiting reactants.<\/p>\n\n\n\n

    \"\"<\/figure>\n","protected":false},"excerpt":{"rendered":"

    The molar mass of CaBr2 is 199.89 g\/mol The Correct Answer and Explanation is: The molar mass of calcium bromide (CaBr2) is calculated by adding the molar masses of its constituent elements, calcium (Ca) and bromine (Br). Now, let’s calculate the molar mass of CaBr2:Molar mass of CaBr2=(Molar mass of Ca)+2\u00d7(Molar mass of Br)\\text{Molar mass of CaBr2} = \\text{(Molar mass of Ca)} + 2 […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-259451","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/259451","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=259451"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/259451\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=259451"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=259451"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=259451"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}