{"id":259652,"date":"2025-07-19T04:50:54","date_gmt":"2025-07-19T04:50:54","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=259652"},"modified":"2025-07-19T04:50:57","modified_gmt":"2025-07-19T04:50:57","slug":"the-element-sodium-na-has-an-atomic-number-11-and-atomic-mass-number-equal-to-22","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/07\/19\/the-element-sodium-na-has-an-atomic-number-11-and-atomic-mass-number-equal-to-22\/","title":{"rendered":"The element Sodium “Na” , has an atomic number 11 and atomic mass number equal to 22"},"content":{"rendered":"\n

The element Sodium “Na” , has an atomic number 11 and atomic mass number equal to 22. When Na (11,22) undergoes beta-plus decay, it produces an element with atomic mass number equal to<\/p>\n\n\n\n

The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n

When sodium (Na) with an atomic number of 11 and an atomic mass number of 22 undergoes beta-plus decay<\/strong> (also known as positron emission<\/strong>), it transforms into a different element.<\/p>\n\n\n\n

Step-by-step Explanation of Beta-Plus Decay:<\/h3>\n\n\n\n

In beta-plus decay, a proton<\/strong> in the nucleus of the atom is converted into a neutron<\/strong>, and a positron<\/strong> (which is the antimatter counterpart of an electron) along with a neutrino<\/strong> are emitted from the nucleus.<\/p>\n\n\n\n

The key points to remember:<\/p>\n\n\n\n

    \n
  • The atomic number<\/strong> decreases by 1<\/strong> because a proton is lost.<\/li>\n\n\n\n
  • The mass number<\/strong> stays the same because the proton is converted into a neutron.<\/li>\n<\/ul>\n\n\n\n

    Initial Element (Na):<\/h4>\n\n\n\n
      \n
    • Atomic number<\/strong> = 11<\/li>\n\n\n\n
    • Mass number<\/strong> = 22<\/li>\n<\/ul>\n\n\n\n

      After Beta-Plus Decay:<\/h4>\n\n\n\n
        \n
      • Atomic number<\/strong> = 11 – 1 = 10<\/strong> (This corresponds to the element Neon (Ne)<\/strong>).<\/li>\n\n\n\n
      • Mass number<\/strong> remains 22<\/strong>, because the total number of nucleons (protons + neutrons) doesn\u2019t change.<\/li>\n<\/ul>\n\n\n\n

        Thus, after beta-plus decay, the resulting element is Neon (Ne)<\/strong> with an atomic number of 10<\/strong> and an atomic mass number of 22<\/strong>.<\/p>\n\n\n\n

        Resulting Element:<\/h3>\n\n\n\n
          \n
        • Neon (Ne)<\/strong> with atomic number = 10<\/strong> and mass number = 22<\/strong>.<\/li>\n<\/ul>\n\n\n\n

          In summary, the atomic mass number remains 22, and the element changes from Sodium (Na) to Neon (Ne) due to the conversion of a proton into a neutron.<\/p>\n\n\n\n

          \"\"<\/figure>\n","protected":false},"excerpt":{"rendered":"

          The element Sodium “Na” , has an atomic number 11 and atomic mass number equal to 22. When Na (11,22) undergoes beta-plus decay, it produces an element with atomic mass number equal to The Correct Answer and Explanation is: When sodium (Na) with an atomic number of 11 and an atomic mass number of 22 […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-259652","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/259652","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=259652"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/259652\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=259652"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=259652"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=259652"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}