{"id":260738,"date":"2025-07-19T16:30:41","date_gmt":"2025-07-19T16:30:41","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=260738"},"modified":"2025-07-19T16:30:43","modified_gmt":"2025-07-19T16:30:43","slug":"find-the-total-area-of-the-shaded-regions-2","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/07\/19\/find-the-total-area-of-the-shaded-regions-2\/","title":{"rendered":"Find the total area of the shaded regions."},"content":{"rendered":"\n<p>Find the total area of the shaded regions. Ay 10 (-2,8) 8 (2,8) y = 2x^2 6 4 2 y = x^4 &#8211; 2x^2 -4 -2 2 4 -2 The area is (Simplify your answer.)<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/07\/image-567.png\" alt=\"\" class=\"wp-image-260742\"\/><\/figure>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-0-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>The correct answer is&nbsp;<strong>128\/15<\/strong>.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation:<\/h3>\n\n\n\n<p>To determine the total area of the shaded regions, we need to calculate the definite integral representing the area between the two given curves: the upper curve&nbsp;y = 2x^2&nbsp;and the lower curve&nbsp;y = x^4 &#8211; 2x^2.<\/p>\n\n\n\n<p><strong>1. Find the Limits of Integration<\/strong><br>First, we find the points where the two curves intersect by setting their equations equal to each other. These intersection points will give us the limits of integration.<br>2x^2 = x^4 &#8211; 2x^2<br>0 = x^4 &#8211; 4x^2<br>Factor out&nbsp;x^2:<br>0 = x^2(x^2 &#8211; 4)<br>Factor the difference of squares&nbsp;(x^2 &#8211; 4):<br>0 = x^2(x &#8211; 2)(x + 2)<br>The solutions are&nbsp;x = 0,&nbsp;x = 2, and&nbsp;x = -2. These are the x-values that bound the shaded regions.<\/p>\n\n\n\n<p><strong>2. Set Up the Integral<\/strong><br>The area between two curves is found by integrating the difference between the upper function and the lower function over the given interval. From the graph,&nbsp;y = 2x^2&nbsp;is the upper curve and&nbsp;y = x^4 &#8211; 2x^2&nbsp;is the lower curve across the entire shaded area, from&nbsp;x = -2&nbsp;to&nbsp;x = 2.<\/p>\n\n\n\n<p>The area (A) is given by the integral:<br>A = \u222b[-2, 2] (upper curve &#8211; lower curve) dx<br>A = \u222b[-2, 2] ( (2x^2) &#8211; (x^4 &#8211; 2x^2) ) dx<br>A = \u222b[-2, 2] (4x^2 &#8211; x^4) dx<\/p>\n\n\n\n<p><strong>3. Use Symmetry to Simplify<\/strong><br>Notice that the shaded area is symmetric with respect to the y-axis. The function we are integrating,&nbsp;f(x) = 4x^2 &#8211; x^4, is an even function because all powers of x are even. We can simplify the calculation by integrating from 0 to 2 and then multiplying the result by 2.<br>A = 2 * \u222b[0, 2] (4x^2 &#8211; x^4) dx<\/p>\n\n\n\n<p><strong>4. Evaluate the Integral<\/strong><br>First, find the antiderivative of the integrand:<br>\u222b(4x^2 &#8211; x^4) dx = 4(x^3\/3) &#8211; (x^5\/5) = (4\/3)x^3 &#8211; (1\/5)x^5<\/p>\n\n\n\n<p>Now, apply the Fundamental Theorem of Calculus to evaluate the definite integral from 0 to 2:<br>A = 2 * [ (4\/3)x^3 &#8211; (1\/5)x^5 ] from 0 to 2<br>A = 2 * ( [ (4\/3)(2)^3 &#8211; (1\/5)(2)^5 ] &#8211; [ (4\/3)(0)^3 &#8211; (1\/5)(0)^5 ] )<br>A = 2 * ( [ (4\/3)(8) &#8211; (1\/5)(32) ] &#8211; 0 )<br>A = 2 * (32\/3 &#8211; 32\/5)<\/p>\n\n\n\n<p>To subtract the fractions, find a common denominator (15):<br>A = 2 * ( (32 * 5)\/(15) &#8211; (32 * 3)\/(15) )<br>A = 2 * ( (160 &#8211; 96)\/15 )<br>A = 2 * (64\/15)<br>A = 128\/15<\/p>\n\n\n\n<p>The total area of the shaded regions is 128\/15.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/07\/learnexams-banner6-1063.jpeg\" alt=\"\" class=\"wp-image-260751\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Find the total area of the shaded regions. Ay 10 (-2,8) 8 (2,8) y = 2x^2 6 4 2 y = x^4 &#8211; 2x^2 -4 -2 2 4 -2 The area is (Simplify your answer.) The Correct Answer and Explanation is: The correct answer is&nbsp;128\/15. Explanation: To determine the total area of the shaded regions, [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-260738","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/260738","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=260738"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/260738\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=260738"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=260738"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=260738"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}