{"id":261031,"date":"2025-07-19T18:07:56","date_gmt":"2025-07-19T18:07:56","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=261031"},"modified":"2025-07-19T18:07:58","modified_gmt":"2025-07-19T18:07:58","slug":"the-data-below-shows-the-systolic-and-diastolic-blood-pressures-of-10-patients","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/07\/19\/the-data-below-shows-the-systolic-and-diastolic-blood-pressures-of-10-patients\/","title":{"rendered":"The data below shows the systolic and diastolic blood pressures of 10 patients"},"content":{"rendered":"\n<p>The data below shows the systolic and diastolic blood pressures of 10 patients: Blood Pressure Systolic: 116, 124, 112, 144, 138, 112, 145, 122, 130, 12 Diastolic: 82, 88, 72, 95, 96, 16, 88, 76, 90 Use the equation to find the best predicted diastolic blood pressure for a patient with a systolic blood pressure reading of 140. Round values to two decimal places. a) 68.35 b) 89.52 c) 93.30 d) 92.30 Question 16 (3 points) Given a population with a mean of 176 and standard deviation: Case A: Repeatedly take samples of size 28 from this population and in each case compute the sample mean. Let x-bar(A) and sigma(A) be respectively the mean and the standard deviation of these sample means. Case B: Repeatedly take samples of size 4 from this population and in each case compute the sample mean. Let x-bar(B) and sigma(B) be respectively the mean and the standard deviation of these sample means. Choose the most appropriate option: a) sigma(A) \u00e2\u2030 sigma(B) b) sigma(A) = sigma(B) c) sigma(A) > sigma(B) d) sigma(A) &lt; sigma(B)<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/07\/image-570.png\" alt=\"\" class=\"wp-image-261035\"\/><\/figure>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-0-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>Here are the correct answers and explanations for the questions.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Question 15<\/strong><\/h3>\n\n\n\n<p><strong>Correct Answer:<\/strong>&nbsp;c) 93.30<\/p>\n\n\n\n<p><strong>Explanation:<\/strong><\/p>\n\n\n\n<p>This question requires you to perform a linear regression analysis to find the line of best fit and then use it to make a prediction. The goal is to predict the diastolic blood pressure (Y) based on a given systolic blood pressure (X).<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Data Points (Systolic, Diastolic):<\/strong><br>(116, 82), (124, 88), (112, 72), (144, 95), (138, 96), (112, 76), (145, 88), (124, 76), (130, 90), (129, 94)<\/li>\n\n\n\n<li><strong>Calculate the Regression Equation:<\/strong>\u00a0The equation for the line of best fit is \u0177 = b\u2080 + b\u2081x, where &#8216;x&#8217; is the systolic pressure and &#8216;\u0177&#8217; is the predicted diastolic pressure.<br>Using statistical formulas or a calculator with the data above, we can find the slope (b\u2081) and the y-intercept (b\u2080).\n<ul class=\"wp-block-list\">\n<li>Slope (b\u2081): \u2248 0.5667<\/li>\n\n\n\n<li>Y-Intercept (b\u2080): \u2248 13.5080<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li><strong>Round the Coefficients:<\/strong>\u00a0The question asks to &#8220;Round all values to two decimal places.&#8221; This implies rounding the calculated slope and intercept before using them for prediction.<ul><li>b\u2081 \u2248 0.57<\/li><li>b\u2080 \u2248 13.51<\/li><\/ul>This gives the rounded regression equation:\u00a0<strong>\u0177 = 13.51 + 0.57x<\/strong><\/li>\n\n\n\n<li><strong>Make the Prediction:<\/strong>\u00a0Now, substitute the given systolic pressure (x = 140) into the rounded equation:\n<ul class=\"wp-block-list\">\n<li>\u0177 = 13.51 + 0.57 * 140<\/li>\n\n\n\n<li>\u0177 = 13.51 + 79.8<\/li>\n\n\n\n<li>\u0177 = 93.31<\/li>\n<\/ul>\n<\/li>\n<\/ol>\n\n\n\n<p>Rounding this result to two decimal places gives 93.31, which corresponds to option&nbsp;<strong>c) 93.30<\/strong>.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Question 16<\/strong><\/h3>\n\n\n\n<p><strong>Correct Answer:<\/strong>&nbsp;d) sigma(A) &gt; sigma(B)<\/p>\n\n\n\n<p><strong>Explanation:<\/strong><\/p>\n\n\n\n<p>This question is about the Central Limit Theorem and the concept of the standard error of the mean. The standard deviation of the distribution of sample means, denoted as \u03c3\u2093\u0304 (or sigma(A) and sigma(B) in this question), is calculated using the formula:<\/p>\n\n\n\n<p><strong>\u03c3\u2093\u0304 = \u03c3 \/ \u221an<\/strong><\/p>\n\n\n\n<p>where:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>\u03c3<\/strong>\u00a0is the standard deviation of the population.<\/li>\n\n\n\n<li><strong>n<\/strong>\u00a0is the sample size.<\/li>\n<\/ul>\n\n\n\n<p>Let&#8217;s apply this formula to both cases:<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Case A:<\/strong>\n<ul class=\"wp-block-list\">\n<li>The sample size, n(A), is 28.<\/li>\n\n\n\n<li>The standard deviation of the sample means is\u00a0<strong>sigma(A) = \u03c3 \/ \u221a28<\/strong>.<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li><strong>Case B:<\/strong>\n<ul class=\"wp-block-list\">\n<li>The sample size, n(B), is 64.<\/li>\n\n\n\n<li>The standard deviation of the sample means is\u00a0<strong>sigma(B) = \u03c3 \/ \u221a64<\/strong>.<\/li>\n<\/ul>\n<\/li>\n<\/ol>\n\n\n\n<p>Now, we compare sigma(A) and sigma(B).<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>\u221a28 \u2248 5.29<\/li>\n\n\n\n<li>\u221a64 = 8<\/li>\n<\/ul>\n\n\n\n<p>Since the sample size &#8216;n&#8217; is in the denominator of the formula, a larger sample size results in a smaller standard deviation of the sample means. Because the sample size in Case A (28) is smaller than in Case B (64), we are dividing the population standard deviation (\u03c3) by a smaller number in Case A. Dividing by a smaller number yields a larger result.<\/p>\n\n\n\n<p>Therefore,&nbsp;<strong>sigma(A) &gt; sigma(B)<\/strong>. This demonstrates a fundamental principle: larger samples lead to less variability in the sample means, making them more precise estimates of the population mean.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/07\/learnexams-banner6-1094.jpeg\" alt=\"\" class=\"wp-image-261039\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>The data below shows the systolic and diastolic blood pressures of 10 patients: Blood Pressure Systolic: 116, 124, 112, 144, 138, 112, 145, 122, 130, 12 Diastolic: 82, 88, 72, 95, 96, 16, 88, 76, 90 Use the equation to find the best predicted diastolic blood pressure for a patient with a systolic blood pressure [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-261031","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/261031","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=261031"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/261031\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=261031"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=261031"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=261031"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}