{"id":261326,"date":"2025-07-20T05:20:58","date_gmt":"2025-07-20T05:20:58","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=261326"},"modified":"2025-07-20T05:21:00","modified_gmt":"2025-07-20T05:21:00","slug":"3-0-ml-of-cyclopentadiene-to-grams-to-moles-2","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/07\/20\/3-0-ml-of-cyclopentadiene-to-grams-to-moles-2\/","title":{"rendered":"3.0 ml of cyclopentadiene to grams to moles"},"content":{"rendered":"\n

3.0 ml of cyclopentadiene to grams to moles<\/p>\n\n\n\n

The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n

To convert 3.0 mL of cyclopentadiene (C\u2085H\u2086) to grams and then to moles, follow these steps:<\/p>\n\n\n\n

Step 1: Convert the Volume of Cyclopentadiene to Mass<\/h3>\n\n\n\n

The density of cyclopentadiene is 0.802 g\/mL at 20\u00b0C. This means that for every milliliter (mL) of cyclopentadiene, it weighs 0.802 grams.<\/p>\n\n\n\n

Using this density, we can calculate the mass of 3.0 mL of cyclopentadiene: Mass=Volume\u00d7Density\\text{Mass} = \\text{Volume} \\times \\text{Density} Mass=Volume\u00d7Density Mass=3.0\u2009mL\u00d70.802\u2009g\/mL=2.406\u2009g\\text{Mass} = 3.0 \\, \\text{mL} \\times 0.802 \\, \\text{g\/mL} = 2.406 \\, \\text{g}Mass=3.0mL\u00d70.802g\/mL=2.406g<\/p>\n\n\n\n

So, 3.0 mL of cyclopentadiene has a mass of 2.406 grams.<\/p>\n\n\n\n

Step 2: Convert the Mass to Moles<\/h3>\n\n\n\n

To convert the mass of cyclopentadiene to moles, we need the molar mass of cyclopentadiene. The molecular formula of cyclopentadiene is C\u2085H\u2086. To find the molar mass: Molar Mass=(5\u00d7Atomic mass of C)+(6\u00d7Atomic mass of H)\\text{Molar Mass} = (5 \\times \\text{Atomic mass of C}) + (6 \\times \\text{Atomic mass of H})Molar Mass=(5\u00d7Atomic mass of C)+(6\u00d7Atomic mass of H) Molar Mass=(5\u00d712.01\u2009g\/mol)+(6\u00d71.008\u2009g\/mol)=60.05\u2009g\/mol+6.048\u2009g\/mol=66.098\u2009g\/mol\\text{Molar Mass} = (5 \\times 12.01 \\, \\text{g\/mol}) + (6 \\times 1.008 \\, \\text{g\/mol}) = 60.05 \\, \\text{g\/mol} + 6.048 \\, \\text{g\/mol} = 66.098 \\, \\text{g\/mol}Molar Mass=(5\u00d712.01g\/mol)+(6\u00d71.008g\/mol)=60.05g\/mol+6.048g\/mol=66.098g\/mol<\/p>\n\n\n\n

Now, to convert the mass of cyclopentadiene to moles: Moles=MassMolar Mass=2.406\u2009g66.098\u2009g\/mol=0.0364\u2009mol\\text{Moles} = \\frac{\\text{Mass}}{\\text{Molar Mass}} = \\frac{2.406 \\, \\text{g}}{66.098 \\, \\text{g\/mol}} = 0.0364 \\, \\text{mol}Moles=Molar MassMass\u200b=66.098g\/mol2.406g\u200b=0.0364mol<\/p>\n\n\n\n

Final Answer:<\/h3>\n\n\n\n
    \n
  • Mass<\/strong>: 3.0 mL of cyclopentadiene weighs 2.406 grams.<\/li>\n\n\n\n
  • Moles<\/strong>: 3.0 mL of cyclopentadiene is 0.0364 moles.<\/li>\n<\/ul>\n\n\n\n

    Explanation:<\/h3>\n\n\n\n
      \n
    1. The density of cyclopentadiene is used to convert volume to mass.<\/li>\n\n\n\n
    2. The molar mass of cyclopentadiene is calculated using the atomic masses of carbon and hydrogen.<\/li>\n\n\n\n
    3. Finally, the mass is divided by the molar mass to determine the number of moles.<\/li>\n<\/ol>\n\n\n\n
      \"\"<\/figure>\n","protected":false},"excerpt":{"rendered":"

      3.0 ml of cyclopentadiene to grams to moles The Correct Answer and Explanation is: To convert 3.0 mL of cyclopentadiene (C\u2085H\u2086) to grams and then to moles, follow these steps: Step 1: Convert the Volume of Cyclopentadiene to Mass The density of cyclopentadiene is 0.802 g\/mL at 20\u00b0C. This means that for every milliliter (mL) […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-261326","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/261326","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=261326"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/261326\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=261326"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=261326"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=261326"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}