{"id":261371,"date":"2025-07-20T05:51:39","date_gmt":"2025-07-20T05:51:39","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=261371"},"modified":"2025-07-20T05:51:42","modified_gmt":"2025-07-20T05:51:42","slug":"what-are-the-magnitude-and-direction-of-the-electric-field-that-will-stop-these-protons-in-a-distance-of-1-40-m-2","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/07\/20\/what-are-the-magnitude-and-direction-of-the-electric-field-that-will-stop-these-protons-in-a-distance-of-1-40-m-2\/","title":{"rendered":"What are the magnitude and direction of the electric field that will stop these protons in a distance of 1.40 m"},"content":{"rendered":"\n<pre id=\"preorder-ask-header-text\" class=\"wp-block-preformatted\">What are the magnitude and direction of the electric field that will stop these protons in a distance of 1.40 m<\/pre>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/07\/image-577.png\" alt=\"\" class=\"wp-image-261372\"\/><\/figure>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p><strong>Magnitude:<\/strong>&nbsp;1.45 x 10\u2074 N\/C<br><strong>Direction:<\/strong>&nbsp;Opposite to the direction of the proton&#8217;s velocity<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation<\/h3>\n\n\n\n<p>To find the magnitude and direction of the electric field, we can apply the work-energy theorem. This theorem states that the net work done on an object is equal to the change in its kinetic energy (W = \u0394KE).<\/p>\n\n\n\n<p>First, let&#8217;s determine the work required to stop the protons. The change in kinetic energy is the final kinetic energy (KE_final) minus the initial kinetic energy (KE_initial). Since the protons are brought to a stop, their final kinetic energy is zero.<\/p>\n\n\n\n<p>\u0394KE = KE_final &#8211; KE_initial = 0 &#8211; (3.25 \u00d7 10\u207b\u00b9\u2075 J) = -3.25 \u00d7 10\u207b\u00b9\u2075 J<\/p>\n\n\n\n<p>The work done (W) by the electric field must be equal to this change in kinetic energy, so W = -3.25 \u00d7 10\u207b\u00b9\u2075 J.<\/p>\n\n\n\n<p>The work done by a constant electric force (F) over a distance (d) is given by the formula W = F * d * cos(\u03b8). To stop the protons, the electric force must act in the direction opposite to their motion. Therefore, the angle \u03b8 between the force and the displacement is 180\u00b0, and cos(180\u00b0) = -1. This gives W = -F * d.<\/p>\n\n\n\n<p>Now we can relate the force to the kinetic energy:<br>-3.25 \u00d7 10\u207b\u00b9\u2075 J = -F * (1.40 m)<br>F = (3.25 \u00d7 10\u207b\u00b9\u2075 J) \/ (1.40 m) = 2.3214 \u00d7 10\u207b\u00b9\u2075 N<\/p>\n\n\n\n<p>The electric force on a charged particle is related to the electric field (E) by the equation F = qE, where q is the charge of the particle. For a proton, the charge is q = 1.602 \u00d7 10\u207b\u00b9\u2079 C. We can rearrange this to solve for the magnitude of the electric field:<\/p>\n\n\n\n<p>E = F \/ q<br>E = (2.3214 \u00d7 10\u207b\u00b9\u2075 N) \/ (1.602 \u00d7 10\u207b\u00b9\u2079 C)<br>E \u2248 14490 N\/C or 1.449 \u00d7 10\u2074 N\/C<\/p>\n\n\n\n<p>Rounding to three significant figures, the magnitude of the electric field is 1.45 \u00d7 10\u2074 N\/C.<\/p>\n\n\n\n<p>For the direction, a proton has a positive charge. The electric force on a positive charge is in the same direction as the electric field. As established, the force must oppose the proton&#8217;s velocity to stop it. Therefore, the electric field must also be directed opposite to the direction of the proton&#8217;s velocity.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/07\/learnexams-banner6-1138.jpeg\" alt=\"\" class=\"wp-image-261373\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>What are the magnitude and direction of the electric field that will stop these protons in a distance of 1.40 m The Correct Answer and Explanation is: Magnitude:&nbsp;1.45 x 10\u2074 N\/CDirection:&nbsp;Opposite to the direction of the proton&#8217;s velocity Explanation To find the magnitude and direction of the electric field, we can apply the work-energy theorem. [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-261371","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/261371","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=261371"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/261371\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=261371"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=261371"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=261371"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}