{"id":262228,"date":"2025-07-20T13:14:50","date_gmt":"2025-07-20T13:14:50","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=262228"},"modified":"2025-07-20T13:14:52","modified_gmt":"2025-07-20T13:14:52","slug":"what-is-the-state-of-hybridization-of-carbon-in-co32-ion-2","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/07\/20\/what-is-the-state-of-hybridization-of-carbon-in-co32-ion-2\/","title":{"rendered":"What is the state of hybridization of carbon in CO32- ion"},"content":{"rendered":"\n

What is the state of hybridization of carbon in CO32- ion?<\/p>\n\n\n\n

The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n

The carbon atom in the carbonate ion, CO\u2083\u00b2\u207b, has a state of sp\u00b2 hybridization<\/strong>.<\/p>\n\n\n\n

Explanation:<\/h3>\n\n\n\n

In the CO\u2083\u00b2\u207b ion, the carbon is bonded to three oxygen atoms. The ion has a trigonal planar geometry, meaning the bond angles between the atoms are approximately 120\u00b0, which suggests that the central atom, carbon, is sp\u00b2 hybridized. Here’s why:<\/p>\n\n\n\n

    \n
  1. Electron Pair Geometry and Bonding<\/strong>:
    Carbon in CO\u2083\u00b2\u207b forms three sigma bonds with the oxygen atoms, which are distributed evenly in a trigonal planar shape. This geometry is consistent with the sp\u00b2 hybridization, which involves the mixing of one s orbital and two p orbitals from carbon to form three sp\u00b2 hybrid orbitals. These hybrid orbitals form sigma bonds with the oxygen atoms.<\/li>\n\n\n\n
  2. Delocalized Electrons<\/strong>:
    The carbonate ion has resonance structures, meaning the double bond between carbon and one oxygen alternates between the three oxygen atoms. This delocalization of electrons over the three oxygen atoms further supports the idea of sp\u00b2 hybridization. The third unhybridized p orbital on carbon is involved in the formation of a pi bond with oxygen atoms, allowing for the resonance of the ion.<\/li>\n\n\n\n
  3. Bond Angles<\/strong>:
    The ideal bond angle for sp\u00b2 hybridization is 120\u00b0, which matches the observed geometry of the CO\u2083\u00b2\u207b ion, confirming that the carbon atom in the ion is sp\u00b2 hybridized.<\/li>\n<\/ol>\n\n\n\n

    Thus, the sp\u00b2 hybridization allows for the correct electron distribution and resonance that stabilizes the carbonate ion.<\/p>\n\n\n\n

    \"\"<\/figure>\n","protected":false},"excerpt":{"rendered":"

    What is the state of hybridization of carbon in CO32- ion? The Correct Answer and Explanation is: The carbon atom in the carbonate ion, CO\u2083\u00b2\u207b, has a state of sp\u00b2 hybridization. Explanation: In the CO\u2083\u00b2\u207b ion, the carbon is bonded to three oxygen atoms. The ion has a trigonal planar geometry, meaning the bond angles […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-262228","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/262228","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=262228"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/262228\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=262228"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=262228"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=262228"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}