{"id":262232,"date":"2025-07-20T13:16:46","date_gmt":"2025-07-20T13:16:46","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=262232"},"modified":"2025-07-20T13:16:48","modified_gmt":"2025-07-20T13:16:48","slug":"what-is-state-of-hybridisation-of-c-in-co32-2","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/07\/20\/what-is-state-of-hybridisation-of-c-in-co32-2\/","title":{"rendered":"What is state of hybridisation of C in CO3^2 &#8211;"},"content":{"rendered":"\n<p>What is state of hybridisation of C in CO3^2 &#8211;<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>The carbon atom in the carbonate ion (CO\u2083\u00b2\u207b) is <strong>sp\u00b2 hybridized<\/strong>.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation:<\/h3>\n\n\n\n<p>The carbonate ion (CO\u2083\u00b2\u207b) has a trigonal planar structure, meaning that all three oxygen atoms are symmetrically arranged around the central carbon atom. The carbon atom forms three sigma bonds with the three oxygen atoms, and since there is no lone pair of electrons on carbon, the electron cloud around the carbon is evenly distributed.<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Electron Domains<\/strong>: The carbon atom has three electron domains around it\u2014one for each of the sigma bonds with oxygen atoms. In the idealized bonding model, the three domains are spread evenly around the carbon in a plane, forming a 120\u00b0 angle between them.<\/li>\n\n\n\n<li><strong>Bonding<\/strong>: The carbon-oxygen bonds in CO\u2083\u00b2\u207b are not purely single bonds, but rather have partial double bond character due to resonance. This means that the bond order between carbon and each oxygen is effectively 1\u2153, which is an average of three equivalent bonds. This delocalization of electrons is possible because of the resonance structures, where the double bond is not fixed to one oxygen but rotates among all three oxygens.<\/li>\n\n\n\n<li><strong>Hybridization<\/strong>: To accommodate the three bonding regions and the trigonal planar geometry, the carbon atom undergoes <strong>sp\u00b2 hybridization<\/strong>. In this hybridization, one s orbital and two p orbitals mix to form three sp\u00b2 hybrid orbitals. These hybrid orbitals form the sigma bonds with the oxygen atoms, while the remaining p orbital on carbon overlaps with the p orbitals on oxygen to form the delocalized pi bonds responsible for the resonance.<\/li>\n<\/ol>\n\n\n\n<h3 class=\"wp-block-heading\">Conclusion:<\/h3>\n\n\n\n<p>Thus, the carbon atom in CO\u2083\u00b2\u207b is <strong>sp\u00b2 hybridized<\/strong> because it forms three equivalent sigma bonds and participates in delocalized pi bonding, leading to a trigonal planar structure with 120\u00b0 bond angles.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/07\/learnexams-banner6-1220.jpeg\" alt=\"\" class=\"wp-image-262233\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>What is state of hybridisation of C in CO3^2 &#8211; The Correct Answer and Explanation is: The carbon atom in the carbonate ion (CO\u2083\u00b2\u207b) is sp\u00b2 hybridized. Explanation: The carbonate ion (CO\u2083\u00b2\u207b) has a trigonal planar structure, meaning that all three oxygen atoms are symmetrically arranged around the central carbon atom. The carbon atom forms [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-262232","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/262232","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=262232"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/262232\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=262232"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=262232"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=262232"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}