{"id":262683,"date":"2025-07-20T18:29:31","date_gmt":"2025-07-20T18:29:31","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=262683"},"modified":"2025-07-20T18:29:33","modified_gmt":"2025-07-20T18:29:33","slug":"what-is-the-oxidation-number-of-chlorine-in-sodium-chlorite-naclo2-2","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/07\/20\/what-is-the-oxidation-number-of-chlorine-in-sodium-chlorite-naclo2-2\/","title":{"rendered":"What is the oxidation number of chlorine in sodium chlorite, NaClO2"},"content":{"rendered":"\n

What is the oxidation number of chlorine in sodium chlorite, NaClO2? a) -1 b) +1 c) +3 d) +5 e) +7<\/p>\n\n\n\n

The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n

The correct answer is c) +3<\/strong>.<\/p>\n\n\n\n

Explanation:<\/h3>\n\n\n\n

To determine the oxidation number of chlorine in sodium chlorite (NaClO\u2082), we can follow these steps:<\/p>\n\n\n\n

    \n
  1. Assign oxidation numbers to other elements:<\/strong>\n
      \n
    • Sodium (Na)<\/strong> is in Group 1 of the periodic table and typically has an oxidation number of +1<\/strong> in its compounds.<\/li>\n\n\n\n
    • Oxygen (O)<\/strong>, in most of its compounds, has an oxidation number of -2<\/strong>.<\/li>\n<\/ul>\n<\/li>\n\n\n\n
    • Set up the equation:<\/strong>
      The compound is neutral overall, so the sum of the oxidation numbers must equal zero. In sodium chlorite (NaClO\u2082), we have one sodium ion (Na\u207a), one chlorine atom (Cl), and two oxygen atoms (O\u2082).<\/li>\n\n\n\n
    • Write the equation for the sum of oxidation numbers:<\/strong>
      • Sodium contributes +1<\/strong>.<\/li>
      • Chlorine contributes an unknown oxidation number, let’s call it x<\/strong>.<\/li>
      • Each oxygen contributes -2<\/strong>, so for two oxygens, that\u2019s -4<\/strong>.<\/li><\/ul>Now, set up the equation: (+1)+x+2(\u22122)=0(+1) + x + 2(-2) = 0(+1)+x+2(\u22122)=0 Simplify the equation: +1+x\u22124=0+1 + x – 4 = 0+1+x\u22124=0 x\u22123=0x – 3 = 0x\u22123=0 x=+3x = +3x=+3<\/li>\n<\/ol>\n\n\n\n

        Thus, the oxidation number of chlorine in NaClO\u2082 is +3<\/strong>.<\/p>\n\n\n\n

        Conclusion:<\/h3>\n\n\n\n

        In sodium chlorite (NaClO\u2082), the chlorine atom has an oxidation number of +3<\/strong>, which is consistent with the choice c) +3<\/strong>.<\/p>\n\n\n\n

        \"\"<\/figure>\n","protected":false},"excerpt":{"rendered":"

        What is the oxidation number of chlorine in sodium chlorite, NaClO2? a) -1 b) +1 c) +3 d) +5 e) +7 The Correct Answer and Explanation is: The correct answer is c) +3. Explanation: To determine the oxidation number of chlorine in sodium chlorite (NaClO\u2082), we can follow these steps: Thus, the oxidation number of […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-262683","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/262683","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=262683"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/262683\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=262683"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=262683"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=262683"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}