{"id":263066,"date":"2025-07-21T04:23:34","date_gmt":"2025-07-21T04:23:34","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=263066"},"modified":"2025-07-21T04:23:36","modified_gmt":"2025-07-21T04:23:36","slug":"the-molecular-mass-of-octane-is-114-22-g-mol-2","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/07\/21\/the-molecular-mass-of-octane-is-114-22-g-mol-2\/","title":{"rendered":"The molecular mass of octane is 114.22 g\/mol"},"content":{"rendered":"\n<p>The molecular mass of octane is 114.22 g\/mol. What is the mass of 22.05 mol of octane? <\/p>\n\n\n\n<p>5.180 g <\/p>\n\n\n\n<p>22.05 g <\/p>\n\n\n\n<p>114.22 g <\/p>\n\n\n\n<p>2,518 g<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\">The correct answer and explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>The correct answer is <strong>2,518 g<\/strong>.<\/p>\n\n\n\n<p>To calculate the mass of 22.05 mol of octane, you can use the formula: Mass=Molar&nbsp;mass\u00d7Number&nbsp;of&nbsp;moles\\text{Mass} = \\text{Molar mass} \\times \\text{Number of moles}<\/p>\n\n\n\n<p>In this case, the molar mass of octane (C\u2088H\u2081\u2088) is given as 114.22 g\/mol, and the number of moles is 22.05 mol. Plugging the values into the formula: Mass=114.22\u2009g\/mol\u00d722.05\u2009mol=2,518.4\u2009g\\text{Mass} = 114.22 \\, \\text{g\/mol} \\times 22.05 \\, \\text{mol} = 2,518.4 \\, \\text{g}<\/p>\n\n\n\n<p>Rounding to the appropriate significant figures (since the number of moles is given to three significant figures), the mass of 22.05 mol of octane is approximately <strong>2,518 g<\/strong>.<\/p>\n\n\n\n<p>This calculation uses the concept of molar mass, which tells you how much one mole of a substance weighs. By multiplying the molar mass by the number of moles, you can determine the total mass of a given quantity of a substance. The unit of grams is used because the molar mass is in grams per mole. Therefore, this method ensures that the mass is expressed in grams.<\/p>\n\n\n\n<p>Understanding how to use the molar mass to find the mass of a substance is important in chemistry, especially when working with reactions, stoichiometry, or when preparing chemical solutions.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>The molecular mass of octane is 114.22 g\/mol. What is the mass of 22.05 mol of octane? 5.180 g 22.05 g 114.22 g 2,518 g The correct answer and explanation is: The correct answer is 2,518 g. To calculate the mass of 22.05 mol of octane, you can use the formula: Mass=Molar&nbsp;mass\u00d7Number&nbsp;of&nbsp;moles\\text{Mass} = \\text{Molar mass} [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-263066","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/263066","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=263066"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/263066\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=263066"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=263066"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=263066"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}