{"id":263077,"date":"2025-07-21T04:28:43","date_gmt":"2025-07-21T04:28:43","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=263077"},"modified":"2025-07-21T04:28:45","modified_gmt":"2025-07-21T04:28:45","slug":"what-is-the-probability-that-a-random-selected-observation-from-the-standard-normal-distribution-is-greater-than-1-04","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/07\/21\/what-is-the-probability-that-a-random-selected-observation-from-the-standard-normal-distribution-is-greater-than-1-04\/","title":{"rendered":"What is the probability that a random selected observation from the standard normal distribution is greater than -1.04"},"content":{"rendered":"\n<p>What is the probability that a random selected observation from the standard normal distribution is greater than -1.04<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\">The correct answer and explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>To find the probability that a randomly selected observation from the standard normal distribution is greater than -1.04, we first need to understand the concept of the standard normal distribution.<\/p>\n\n\n\n<p>A standard normal distribution has a mean of 0 and a standard deviation of 1. The area under the curve represents the total probability, which is 1. The value -1.04 is a z-score, which indicates how many standard deviations an observation is from the mean.<\/p>\n\n\n\n<p>To calculate the probability that a random observation is greater than -1.04, we first need to find the cumulative probability up to -1.04, which corresponds to the area to the left of -1.04. This cumulative probability can be found using a z-table or a statistical calculator.<\/p>\n\n\n\n<p>From the z-table, the cumulative probability at -1.04 is approximately 0.1492. This means that about 14.92% of the observations fall below -1.04. Since the total area under the curve is 1, the probability of selecting a value greater than -1.04 is the complement of the cumulative probability.<\/p>\n\n\n\n<p>Thus, the probability is: P(X&gt;\u22121.04)=1\u2212P(X\u2264\u22121.04)=1\u22120.1492=0.8508P(X &gt; -1.04) = 1 &#8211; P(X \\leq -1.04) = 1 &#8211; 0.1492 = 0.8508<\/p>\n\n\n\n<p>Therefore, the probability that a randomly selected observation is greater than -1.04 is approximately 0.8508, or 85.08%.<\/p>\n\n\n\n<p>This result makes sense because -1.04 is relatively close to the left tail of the standard normal distribution, and since the distribution is symmetric, the majority of the data (about 85%) lies to the right of this value.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>What is the probability that a random selected observation from the standard normal distribution is greater than -1.04 The correct answer and explanation is: To find the probability that a randomly selected observation from the standard normal distribution is greater than -1.04, we first need to understand the concept of the standard normal distribution. A [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-263077","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/263077","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=263077"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/263077\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=263077"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=263077"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=263077"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}