What is the largest size gallon container of mercury, SG = 13.6, if you wish to restrict the weight to 50 pounds (neglecting the weight of the container itself)?<\/p>\n\n\n\n
The correct answer and explanation is:<\/mark><\/strong><\/p>\n\n\n\n To solve this problem, we first need to understand the relationship between the weight, volume, and specific gravity (SG) of mercury. The specific gravity of a substance is the ratio of its density to the density of water. Since the density of water is 62.4 pounds per cubic foot (lb\/ft\u00b3), the density of mercury will be: Density of mercury=SG\u00d7Density of water=13.6\u00d762.4\u2009lb\/ft3=850.64\u2009lb\/ft3\\text{Density of mercury} = \\text{SG} \\times \\text{Density of water} = 13.6 \\times 62.4 \\, \\text{lb\/ft}^3 = 850.64 \\, \\text{lb\/ft}^3<\/p>\n\n\n\n Next, we need to relate the weight (50 pounds) to the volume of mercury. The weight of an object is calculated by multiplying the volume by the density: Weight=Density\u00d7Volume\\text{Weight} = \\text{Density} \\times \\text{Volume}<\/p>\n\n\n\n Given that the weight should be 50 pounds: 50\u2009lb=850.64\u2009lb\/ft3\u00d7Volume50 \\, \\text{lb} = 850.64 \\, \\text{lb\/ft}^3 \\times \\text{Volume}<\/p>\n\n\n\n Solving for the volume: Volume=50\u2009lb850.64\u2009lb\/ft3=0.0588\u2009ft3\\text{Volume} = \\frac{50 \\, \\text{lb}}{850.64 \\, \\text{lb\/ft}^3} = 0.0588 \\, \\text{ft}^3<\/p>\n\n\n\n Now, we need to convert this volume into gallons. Since 1 cubic foot equals 7.48 gallons: Volume in gallons=0.0588\u2009ft3\u00d77.48\u2009gallons\/ft3=0.440\u2009gallons\\text{Volume in gallons} = 0.0588 \\, \\text{ft}^3 \\times 7.48 \\, \\text{gallons\/ft}^3 = 0.440 \\, \\text{gallons}<\/p>\n\n\n\n Thus, the largest size gallon container of mercury that would weigh 50 pounds is approximately 0.44 gallons<\/strong>.<\/p>\n\n\n\n This calculation neglects the weight of the container itself, focusing solely on the weight of the mercury.<\/p>\n","protected":false},"excerpt":{"rendered":" What is the largest size gallon container of mercury, SG = 13.6, if you wish to restrict the weight to 50 pounds (neglecting the weight of the container itself)? The correct answer and explanation is: To solve this problem, we first need to understand the relationship between the weight, volume, and specific gravity (SG) of […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-263695","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/263695","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=263695"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/263695\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=263695"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=263695"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=263695"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}