{"id":263810,"date":"2025-07-21T09:04:26","date_gmt":"2025-07-21T09:04:26","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=263810"},"modified":"2025-07-21T09:04:28","modified_gmt":"2025-07-21T09:04:28","slug":"calculate-the-molar-mass-of-pbco32","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/07\/21\/calculate-the-molar-mass-of-pbco32\/","title":{"rendered":"Calculate the molar mass of Pb(CO3)2"},"content":{"rendered":"\n<pre id=\"preorder-ask-header-text\" class=\"wp-block-preformatted\">Calculate the molar mass of Pb(CO3)2<\/pre>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>To calculate the molar mass of <strong>Pb(CO3)2<\/strong>, we first need to break down the compound and find the molar masses of each element in it.<\/p>\n\n\n\n<p><strong>Step 1: Identify the components in Pb(CO3)2<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The formula <strong>Pb(CO3)2<\/strong> tells us that the compound consists of one lead (Pb) atom and two carbonate ions (CO3)\u00b2\u207b.<\/li>\n<\/ul>\n\n\n\n<p><strong>Step 2: Find the molar masses of the elements<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Pb<\/strong> (Lead) has a molar mass of approximately <strong>207.2 g\/mol<\/strong>.<\/li>\n\n\n\n<li><strong>C<\/strong> (Carbon) has a molar mass of approximately <strong>12.01 g\/mol<\/strong>.<\/li>\n\n\n\n<li><strong>O<\/strong> (Oxygen) has a molar mass of approximately <strong>16.00 g\/mol<\/strong>.<\/li>\n<\/ul>\n\n\n\n<p><strong>Step 3: Calculate the mass of the carbonate ion (CO3)<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Each carbonate ion (CO3) consists of one carbon (C) atom and three oxygen (O) atoms.<\/li>\n\n\n\n<li>The mass of one CO3 group is: 12.01\u2009g\/mol\u2009(C)+3\u00d716.00\u2009g\/mol\u2009(O)=12.01\u2009g\/mol+48.00\u2009g\/mol=60.01\u2009g\/mol12.01 \\, \\text{g\/mol} \\, (\\text{C}) + 3 \\times 16.00 \\, \\text{g\/mol} \\, (\\text{O}) = 12.01 \\, \\text{g\/mol} + 48.00 \\, \\text{g\/mol} = 60.01 \\, \\text{g\/mol}12.01g\/mol(C)+3\u00d716.00g\/mol(O)=12.01g\/mol+48.00g\/mol=60.01g\/mol<\/li>\n\n\n\n<li>Since there are two carbonate ions (CO3)\u00b2\u207b in Pb(CO3)2, the total mass of the carbonate part of the molecule is: 2\u00d760.01\u2009g\/mol=120.02\u2009g\/mol2 \\times 60.01 \\, \\text{g\/mol} = 120.02 \\, \\text{g\/mol}2\u00d760.01g\/mol=120.02g\/mol<\/li>\n<\/ul>\n\n\n\n<p><strong>Step 4: Add the molar masses together<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Now, add the molar mass of lead (Pb) and the total molar mass of the two carbonate ions (CO3)\u00b2\u207b: 207.2\u2009g\/mol(Pb)+120.02\u2009g\/mol(CO3)=327.22\u2009g\/mol207.2 \\, \\text{g\/mol} (\\text{Pb}) + 120.02 \\, \\text{g\/mol} (\\text{CO3}) = 327.22 \\, \\text{g\/mol}207.2g\/mol(Pb)+120.02g\/mol(CO3)=327.22g\/mol<\/li>\n<\/ul>\n\n\n\n<p><strong>Final Answer:<\/strong><br>The molar mass of Pb(CO3)2 is <strong>327.22 g\/mol<\/strong>.<\/p>\n\n\n\n<p>This method involves adding the individual molar masses of each element, taking into account the number of atoms of each in the compound. This approach is useful for determining the molar mass of any molecular compound.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/07\/learnexams-banner6-1328.jpeg\" alt=\"\" class=\"wp-image-263811\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Calculate the molar mass of Pb(CO3)2 The Correct Answer and Explanation is: To calculate the molar mass of Pb(CO3)2, we first need to break down the compound and find the molar masses of each element in it. Step 1: Identify the components in Pb(CO3)2 Step 2: Find the molar masses of the elements Step 3: [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-263810","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/263810","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=263810"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/263810\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=263810"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=263810"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=263810"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}