To convert the concentration of Ca2+\\text{Ca}^{2+}Ca2+ in meq\/L to mmol\/L, we need to understand the relationship between milliequivalents (meq) and millimoles (mmol).<\/p>\n\n\n\n
- \n
- Understanding Equivalents and Moles<\/strong>:\n
- \n
- The term equivalent<\/strong> refers to the amount of a substance that will combine with or replace 1 mole of hydrogen ions (H+) or 1 mole of electrons. For ions like Ca2+\\text{Ca}^{2+}Ca2+, the equivalent corresponds to its valence (charge).<\/li>\n\n\n\n
- The valence<\/strong> of Ca2+\\text{Ca}^{2+}Ca2+ is 2 because it carries a charge of +2.<\/li>\n<\/ul>\n<\/li>\n\n\n\n
- Conversion Factor<\/strong>:\n
- \n
- 1 equivalent (eq) of Ca2+\\text{Ca}^{2+}Ca2+ is equal to 1 mole of Ca2+\\text{Ca}^{2+}Ca2+ ions divided by its valence (which is 2). Therefore: 1\u00a0eq\u00a0of\u00a0Ca2+=1\u00a0mole\u00a0of\u00a0Ca2+\u00f721 \\text{ eq of } \\text{Ca}^{2+} = 1 \\text{ mole of Ca}^{2+} \\div 21\u00a0eq\u00a0of\u00a0Ca2+=1\u00a0mole\u00a0of\u00a0Ca2+\u00f72<\/li>\n\n\n\n
- To convert from meq (milliequivalents) to mmol (millimoles), we use the fact that: 1\u00a0meq\u00a0of\u00a0Ca2+=12\u00a0mmol\u00a0of\u00a0Ca2+1 \\text{ meq of } \\text{Ca}^{2+} = \\frac{1}{2} \\text{ mmol of Ca}^{2+}1\u00a0meq\u00a0of\u00a0Ca2+=21\u200b\u00a0mmol\u00a0of\u00a0Ca2+ This is because 1 meq corresponds to 11000\\frac{1}{1000}10001\u200b of an equivalent, and each equivalent corresponds to half a mole of Ca2+\\text{Ca}^{2+}Ca2+.<\/li>\n<\/ul>\n<\/li>\n\n\n\n
- Calculation<\/strong>:\n
- \n
- You are given a concentration of 2.50 meq\/L for the Ca2+\\text{Ca}^{2+}Ca2+ solution.<\/li>\n\n\n\n
- To convert this to mmol\/L: Concentration\u00a0in\u00a0mmol\/L=2.50\u00a0meq\/L\u00d712=1.25\u00a0mmol\/L\\text{Concentration in mmol\/L} = 2.50 \\text{ meq\/L} \\times \\frac{1}{2} = 1.25 \\text{ mmol\/L}Concentration\u00a0in\u00a0mmol\/L=2.50\u00a0meq\/L\u00d721\u200b=1.25\u00a0mmol\/L<\/li>\n<\/ul>\n<\/li>\n<\/ol>\n\n\n\n
Thus, the concentration of Ca2+\\text{Ca}^{2+}Ca2+ in the solution is 1.25 mmol\/L<\/strong>.<\/p>\n\n\n\n
![\"\"](\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/07\/learnexams-banner6-1470.jpeg\")
<\/figure>\n","protected":false},"excerpt":{"rendered":"What is the concentration in mmol\/L of a Ca2+ solution that is 2.50 meq\/L? The Correct Answer and Explanation is: To convert the concentration of Ca2+\\text{Ca}^{2+}Ca2+ in meq\/L to mmol\/L, we need to understand the relationship between milliequivalents (meq) and millimoles (mmol). Thus, the concentration of Ca2+\\text{Ca}^{2+}Ca2+ in the solution is 1.25 mmol\/L.<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-265486","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/265486","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=265486"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/265486\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=265486"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=265486"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=265486"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}
- The valence<\/strong> of Ca2+\\text{Ca}^{2+}Ca2+ is 2 because it carries a charge of +2.<\/li>\n<\/ul>\n<\/li>\n\n\n\n
- The term equivalent<\/strong> refers to the amount of a substance that will combine with or replace 1 mole of hydrogen ions (H+) or 1 mole of electrons. For ions like Ca2+\\text{Ca}^{2+}Ca2+, the equivalent corresponds to its valence (charge).<\/li>\n\n\n\n