To calculate the molar mass of argon atoms, given that the mass of a single atom is 6.634\u00d710\u2212266.634 \\times 10^{-26}6.634\u00d710\u221226 kg, we can proceed as follows:<\/p>\n\n\n\n
Step 1: Understand the concept of molar mass<\/h3>\n\n\n\n
The molar mass of an element is the mass of one mole of its atoms. One mole of atoms contains Avogadro’s number of particles, which is approximately 6.022\u00d710236.022 \\times 10^{23}6.022\u00d71023 atoms. The molar mass is usually expressed in grams per mole (g\/mol).<\/p>\n\n\n\n
Step 2: Convert the mass of a single atom to the molar mass<\/h3>\n\n\n\n
Given that the mass of a single argon atom is 6.634\u00d710\u2212266.634 \\times 10^{-26}6.634\u00d710\u221226 kg, we need to convert this mass to grams (since 1 kg = 1000 grams). So, the mass of a single argon atom in grams is:6.634\u00d710\u221226\u2009kg\u00d71000=6.634\u00d710\u221223\u2009grams6.634 \\times 10^{-26} \\, \\text{kg} \\times 1000 = 6.634 \\times 10^{-23} \\, \\text{grams}6.634\u00d710\u221226kg\u00d71000=6.634\u00d710\u221223grams<\/p>\n\n\n\n
Step 3: Multiply by Avogadro’s number<\/h3>\n\n\n\n
Now, to find the molar mass, we multiply the mass of a single atom by Avogadro’s number (6.022\u00d710236.022 \\times 10^{23}6.022\u00d71023 atoms per mole):Molar mass=(6.634\u00d710\u221223\u2009g)\u00d7(6.022\u00d71023\u2009atoms\/mol)\\text{Molar mass} = (6.634 \\times 10^{-23} \\, \\text{g}) \\times (6.022 \\times 10^{23} \\, \\text{atoms\/mol})Molar mass=(6.634\u00d710\u221223g)\u00d7(6.022\u00d71023atoms\/mol)<\/p>\n\n\n\n
This simplifies to:Molar mass=39.98\u2009g\/mol\\text{Molar mass} = 39.98 \\, \\text{g\/mol}Molar mass=39.98g\/mol<\/p>\n\n\n\n
Step 4: Conclusion<\/h3>\n\n\n\n
Therefore, the molar mass of argon is approximately 40.0 g\/mol<\/strong>, which matches the standard atomic weight of argon.<\/p>\n\n\n\n This calculation uses the fact that the molar mass is simply the mass of a mole of atoms, and it relies on basic unit conversions and the relationship between atomic mass and Avogadro’s number.<\/p>\n\n\n\n Calculate the molar mass of argon atoms given that the mass of a single atom is 6.634\u00c3\u201410^-26 kg. The Correct Answer and Explanation is: To calculate the molar mass of argon atoms, given that the mass of a single atom is 6.634\u00d710\u2212266.634 \\times 10^{-26}6.634\u00d710\u221226 kg, we can proceed as follows: Step 1: Understand the concept […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-266009","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/266009","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=266009"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/266009\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=266009"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=266009"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=266009"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}![\"\"](\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/07\/learnexams-banner6-1527.jpeg\")
<\/figure>\n","protected":false},"excerpt":{"rendered":"