{"id":266259,"date":"2025-07-22T17:58:38","date_gmt":"2025-07-22T17:58:38","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=266259"},"modified":"2025-07-22T17:58:43","modified_gmt":"2025-07-22T17:58:43","slug":"how-many-moles-of-sodium-carbonate-na2co3-contain-1-773-1017-carbon-atoms","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/07\/22\/how-many-moles-of-sodium-carbonate-na2co3-contain-1-773-1017-carbon-atoms\/","title":{"rendered":"How many moles of sodium carbonate Na2CO3 contain 1.773 * 10^17 carbon atoms"},"content":{"rendered":"\n

How many moles of sodium carbonate Na2CO3 contain 1.773 * 10^17 carbon atoms? A) 8.836 * 10^-7 B) 5.590 * 10^-7 C) 1.473 * 10^-7 D) 2.945 * 10^-7<\/p>\n\n\n\n

The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n

To solve for the number of moles of sodium carbonate (Na2CO3) that contain 1.773 \u00d7 10\u00b9\u2077 carbon atoms, we can break the problem into a few steps:<\/p>\n\n\n\n

Step 1: Determine the number of carbon atoms in one mole of Na2CO3.<\/h3>\n\n\n\n

Each Na2CO3 molecule contains one carbon atom, so one mole of Na2CO3 contains 1 mole of carbon atoms<\/strong>.<\/p>\n\n\n\n

Step 2: Use Avogadro’s number.<\/h3>\n\n\n\n

Avogadro’s number is 6.022 \u00d7 10\u00b2\u00b3 atoms\/mole<\/strong>, which is the number of atoms (or molecules) in one mole of a substance.<\/p>\n\n\n\n

Step 3: Set up the proportion.<\/h3>\n\n\n\n

We are given 1.773 \u00d7 10\u00b9\u2077 carbon atoms<\/strong>, and we want to find the number of moles of Na2CO3 that contain this number of carbon atoms. We can set up the following proportion:Number of moles of Na2CO3=Number of carbon atoms givenAvogadro\u2019s number\\text{Number of moles of Na2CO3} = \\frac{\\text{Number of carbon atoms given}}{\\text{Avogadro’s number}}Number of moles of Na2CO3=Avogadro\u2019s numberNumber of carbon atoms given\u200b<\/p>\n\n\n\n

Substitute the values:Number of moles of Na2CO3=1.773\u00d71017 atoms6.022\u00d71023 atoms\/mole\\text{Number of moles of Na2CO3} = \\frac{1.773 \\times 10^{17} \\text{ atoms}}{6.022 \\times 10^{23} \\text{ atoms\/mole}}Number of moles of Na2CO3=6.022\u00d71023 atoms\/mole1.773\u00d71017 atoms\u200b<\/p>\n\n\n\n

Step 4: Perform the calculation.<\/h3>\n\n\n\n

Number of moles of Na2CO3=2.945\u00d710\u22127 moles\\text{Number of moles of Na2CO3} = 2.945 \\times 10^{-7} \\text{ moles}Number of moles of Na2CO3=2.945\u00d710\u22127 moles<\/p>\n\n\n\n

Conclusion:<\/h3>\n\n\n\n

Thus, the number of moles of sodium carbonate Na2CO3 that contain 1.773 \u00d7 10\u00b9\u2077 carbon atoms is 2.945 \u00d7 10\u207b\u2077<\/strong> moles.<\/p>\n\n\n\n

So, the correct answer is D) 2.945 \u00d7 10\u207b\u2077<\/strong>.<\/p>\n\n\n\n

\"\"<\/figure>\n","protected":false},"excerpt":{"rendered":"

How many moles of sodium carbonate Na2CO3 contain 1.773 * 10^17 carbon atoms? A) 8.836 * 10^-7 B) 5.590 * 10^-7 C) 1.473 * 10^-7 D) 2.945 * 10^-7 The Correct Answer and Explanation is: To solve for the number of moles of sodium carbonate (Na2CO3) that contain 1.773 \u00d7 10\u00b9\u2077 carbon atoms, we can […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-266259","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/266259","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=266259"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/266259\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=266259"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=266259"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=266259"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}