{"id":266304,"date":"2025-07-22T19:40:28","date_gmt":"2025-07-22T19:40:28","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=266304"},"modified":"2025-07-22T19:40:30","modified_gmt":"2025-07-22T19:40:30","slug":"how-many-moles-of-sodium-carbonate-na2co3-contain-1-773-1017-carbon-atoms-2","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/07\/22\/how-many-moles-of-sodium-carbonate-na2co3-contain-1-773-1017-carbon-atoms-2\/","title":{"rendered":"How many moles of sodium carbonate Na2CO3 contain 1.773 * 10^17 carbon atoms"},"content":{"rendered":"\n<pre id=\"preorder-ask-header-text\" class=\"wp-block-preformatted\">How many moles of sodium carbonate Na2CO3 contain 1.773 * 10^17 carbon atoms? A) 8.836 * 10^-7 B) 5.590 * 10^-7 C) 1.473 * 10^-7 D) 2.945 * 10^-7<\/pre>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-0-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>To solve this, we can use the concept of Avogadro\u2019s number and stoichiometry. Here&#8217;s the step-by-step solution:<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Determine the relationship between carbon atoms and moles of sodium carbonate:<\/strong> Sodium carbonate (Na\u2082CO\u2083) contains 1 carbon atom per formula unit. Therefore, the number of moles of sodium carbonate will be directly related to the number of moles of carbon atoms present.<\/li>\n\n\n\n<li><strong>Convert carbon atoms to moles of carbon:<\/strong> Avogadro\u2019s number (6.022 \u00d7 10\u00b2\u00b3 atoms\/mol) tells us how many atoms there are in one mole of a substance. To find the number of moles of carbon atoms, use the following relation: Moles\u00a0of\u00a0carbon=Number\u00a0of\u00a0carbon\u00a0atomsAvogadro\u2019s\u00a0number=1.773\u00d710176.022\u00d71023\\text{Moles of carbon} = \\frac{\\text{Number of carbon atoms}}{\\text{Avogadro\u2019s number}} = \\frac{1.773 \\times 10^{17}}{6.022 \\times 10^{23}} Moles\u00a0of\u00a0carbon=Avogadro\u2019s\u00a0numberNumber\u00a0of\u00a0carbon\u00a0atoms\u200b=6.022\u00d710231.773\u00d71017\u200b Let&#8217;s perform this calculation: Moles\u00a0of\u00a0carbon=1.773\u00d710176.022\u00d71023=2.945\u00d710\u22127\u00a0moles\u00a0of\u00a0carbon\\text{Moles of carbon} = \\frac{1.773 \\times 10^{17}}{6.022 \\times 10^{23}} = 2.945 \\times 10^{-7} \\text{ moles of carbon}Moles\u00a0of\u00a0carbon=6.022\u00d710231.773\u00d71017\u200b=2.945\u00d710\u22127\u00a0moles\u00a0of\u00a0carbon<\/li>\n\n\n\n<li><strong>Calculate the moles of sodium carbonate:<\/strong> Since each Na\u2082CO\u2083 unit contains 1 carbon atom, the number of moles of sodium carbonate is the same as the number of moles of carbon. Therefore: Moles\u00a0of\u00a0sodium\u00a0carbonate=2.945\u00d710\u22127\u00a0moles\\text{Moles of sodium carbonate} = 2.945 \\times 10^{-7} \\text{ moles}Moles\u00a0of\u00a0sodium\u00a0carbonate=2.945\u00d710\u22127\u00a0moles<\/li>\n<\/ol>\n\n\n\n<p>Thus, the correct answer is <strong>D) 2.945 \u00d7 10\u207b\u2077<\/strong>.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation:<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The key concept here is the 1:1 ratio of carbon atoms to sodium carbonate formula units in Na\u2082CO\u2083. This makes the calculation straightforward: the number of moles of carbon atoms directly translates to the number of moles of sodium carbonate.<\/li>\n\n\n\n<li>Using Avogadro&#8217;s number allows us to relate the count of individual atoms to macroscopic quantities (moles).<\/li>\n<\/ul>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/07\/learnexams-banner6-1574.jpeg\" alt=\"\" class=\"wp-image-266305\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>How many moles of sodium carbonate Na2CO3 contain 1.773 * 10^17 carbon atoms? A) 8.836 * 10^-7 B) 5.590 * 10^-7 C) 1.473 * 10^-7 D) 2.945 * 10^-7 The Correct Answer and Explanation is: To solve this, we can use the concept of Avogadro\u2019s number and stoichiometry. Here&#8217;s the step-by-step solution: Thus, the correct [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-266304","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/266304","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=266304"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/266304\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=266304"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=266304"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=266304"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}