{"id":266407,"date":"2025-07-23T06:04:52","date_gmt":"2025-07-23T06:04:52","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=266407"},"modified":"2025-07-23T06:04:55","modified_gmt":"2025-07-23T06:04:55","slug":"vs-7-07-vrms-put-r1-1k-vgg-max-9v-question-1-compute-the-firing-angle-if-vgg-is-set-to-50","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/07\/23\/vs-7-07-vrms-put-r1-1k-vgg-max-9v-question-1-compute-the-firing-angle-if-vgg-is-set-to-50\/","title":{"rendered":"VS 7.07 Vrms PUT R1 1K VGG Max 9V Question 1 Compute the firing angle, if VGG is set to 50%"},"content":{"rendered":"\n<p>VS 7.07 Vrms PUT R1 1K VGG Max 9V Question 1 Compute the firing angle, if VGG is set to 50%. Do not include the units, the final answer must be in 2 decimal places. Question 2 Compute the firing angle, if VGG is set to 80%. Do not include the units, the final answer must be in 2 decimal places.<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>Let&#8217;s solve both questions step by step.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Given:<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Vrms=7.07V_{rms} = 7.07Vrms\u200b=7.07 V<\/li>\n\n\n\n<li>R1=1R_1 = 1R1\u200b=1 k\u03a9<\/li>\n\n\n\n<li>VGGV_{GG}VGG\u200b (control voltage) can be set to 50% and 80%.<\/li>\n\n\n\n<li>The maximum VGGV_{GG}VGG\u200b is 9V.<\/li>\n<\/ul>\n\n\n\n<p>We are asked to compute the firing angle (\u03b1\\alpha\u03b1) in two scenarios.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Formula for the Firing Angle:<\/strong><\/h3>\n\n\n\n<p>The firing angle \u03b1\\alpha\u03b1 is related to the control voltage VGGV_{GG}VGG\u200b in a phase-controlled rectifier circuit. The relationship can be described as:VGG=Vmax\u00d7(1\u2212cos\u2061\u03b1)V_{GG} = V_{max} \\times (1 &#8211; \\cos \\alpha)VGG\u200b=Vmax\u200b\u00d7(1\u2212cos\u03b1)<\/p>\n\n\n\n<p>Where:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>VmaxV_{max}Vmax\u200b is the peak value of the voltage (i.e., Vmax=Vrms\u00d72V_{max} = V_{rms} \\times \\sqrt{2}Vmax\u200b=Vrms\u200b\u00d72\u200b).<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\">Step 1: Find VmaxV_{max}Vmax\u200b<\/h3>\n\n\n\n<p>Since Vrms=7.07V_{rms} = 7.07Vrms\u200b=7.07 V,Vmax=7.07\u00d72=7.07\u00d71.414=10\u2009VV_{max} = 7.07 \\times \\sqrt{2} = 7.07 \\times 1.414 = 10 \\, \\text{V}Vmax\u200b=7.07\u00d72\u200b=7.07\u00d71.414=10V<\/p>\n\n\n\n<p>Thus, Vmax=10V_{max} = 10Vmax\u200b=10 V.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>For Question 1: When VGG=50%V_{GG} = 50\\%VGG\u200b=50% of 9V<\/strong><\/h3>\n\n\n\n<p>This means VGG=0.5\u00d79=4.5V_{GG} = 0.5 \\times 9 = 4.5VGG\u200b=0.5\u00d79=4.5 V.<\/p>\n\n\n\n<p>Now, substitute this into the formula:VGG=Vmax\u00d7(1\u2212cos\u2061\u03b1)V_{GG} = V_{max} \\times (1 &#8211; \\cos \\alpha)VGG\u200b=Vmax\u200b\u00d7(1\u2212cos\u03b1)4.5=10\u00d7(1\u2212cos\u2061\u03b1)4.5 = 10 \\times (1 &#8211; \\cos \\alpha)4.5=10\u00d7(1\u2212cos\u03b1)<\/p>\n\n\n\n<p>Solving for cos\u2061\u03b1\\cos \\alphacos\u03b1:1\u2212cos\u2061\u03b1=4.510=0.451 &#8211; \\cos \\alpha = \\frac{4.5}{10} = 0.451\u2212cos\u03b1=104.5\u200b=0.45cos\u2061\u03b1=1\u22120.45=0.55\\cos \\alpha = 1 &#8211; 0.45 = 0.55cos\u03b1=1\u22120.45=0.55<\/p>\n\n\n\n<p>Now, calculate \u03b1\\alpha\u03b1:\u03b1=cos\u2061\u22121(0.55)\u224856.25\u2218\\alpha = \\cos^{-1}(0.55) \\approx 56.25^\\circ\u03b1=cos\u22121(0.55)\u224856.25\u2218<\/p>\n\n\n\n<p>So, the firing angle is <strong>56.25<\/strong> degrees.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>For Question 2: When VGG=80%V_{GG} = 80\\%VGG\u200b=80% of 9V<\/strong><\/h3>\n\n\n\n<p>This means VGG=0.8\u00d79=7.2V_{GG} = 0.8 \\times 9 = 7.2VGG\u200b=0.8\u00d79=7.2 V.<\/p>\n\n\n\n<p>Substitute into the formula:VGG=Vmax\u00d7(1\u2212cos\u2061\u03b1)V_{GG} = V_{max} \\times (1 &#8211; \\cos \\alpha)VGG\u200b=Vmax\u200b\u00d7(1\u2212cos\u03b1)7.2=10\u00d7(1\u2212cos\u2061\u03b1)7.2 = 10 \\times (1 &#8211; \\cos \\alpha)7.2=10\u00d7(1\u2212cos\u03b1)<\/p>\n\n\n\n<p>Solving for cos\u2061\u03b1\\cos \\alphacos\u03b1:1\u2212cos\u2061\u03b1=7.210=0.721 &#8211; \\cos \\alpha = \\frac{7.2}{10} = 0.721\u2212cos\u03b1=107.2\u200b=0.72cos\u2061\u03b1=1\u22120.72=0.28\\cos \\alpha = 1 &#8211; 0.72 = 0.28cos\u03b1=1\u22120.72=0.28<\/p>\n\n\n\n<p>Now, calculate \u03b1\\alpha\u03b1:\u03b1=cos\u2061\u22121(0.28)\u224873.74\u2218\\alpha = \\cos^{-1}(0.28) \\approx 73.74^\\circ\u03b1=cos\u22121(0.28)\u224873.74\u2218<\/p>\n\n\n\n<p>So, the firing angle is <strong>73.74<\/strong> degrees.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Final Answers:<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>For Question 1:<\/strong> The firing angle is <strong>56.25<\/strong> degrees.<\/li>\n\n\n\n<li><strong>For Question 2:<\/strong> The firing angle is <strong>73.74<\/strong> degrees.<\/li>\n<\/ul>\n\n\n\n<p>These calculations assume ideal conditions where there is no significant loss or variation in the system.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/07\/learnexams-banner6-1592.jpeg\" alt=\"\" class=\"wp-image-266623\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>VS 7.07 Vrms PUT R1 1K VGG Max 9V Question 1 Compute the firing angle, if VGG is set to 50%. Do not include the units, the final answer must be in 2 decimal places. Question 2 Compute the firing angle, if VGG is set to 80%. Do not include the units, the final answer [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-266407","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/266407","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=266407"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/266407\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=266407"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=266407"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=266407"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}