{"id":266722,"date":"2025-07-23T06:41:33","date_gmt":"2025-07-23T06:41:33","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=266722"},"modified":"2025-07-23T06:41:44","modified_gmt":"2025-07-23T06:41:44","slug":"what-is-the-formula-for-chromium-ii-acetate","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/07\/23\/what-is-the-formula-for-chromium-ii-acetate\/","title":{"rendered":"What is the formula for chromium (II) acetate"},"content":{"rendered":"\n<p>What is the formula for chromium (II) acetate?<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\">The correct answer and explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>The formula for chromium (II) acetate is <strong>Cr(C\u2082H\u2083O\u2082)\u2082<\/strong>.<\/p>\n\n\n\n<p>Explanation:<br>Chromium (II) acetate consists of chromium in the +2 oxidation state and acetate ions. The acetate ion (C\u2082H\u2083O\u2082\u207b) is a common polyatomic ion, made up of two carbon atoms, three hydrogen atoms, and two oxygen atoms. Each acetate ion carries a negative charge of -1.<\/p>\n\n\n\n<p>To determine the formula of chromium (II) acetate, you must first understand the charges involved. Chromium (II) indicates that chromium has a +2 charge in this compound. The acetate ion, being a monovalent anion, has a charge of -1. To balance the charges, two acetate ions are needed to neutralize the +2 charge of chromium.<\/p>\n\n\n\n<p>Thus, the formula is:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Cr\u00b2\u207a<\/strong> (chromium with a +2 charge)<\/li>\n\n\n\n<li>Two <strong>C\u2082H\u2083O\u2082\u207b<\/strong> (acetate) ions, each with a -1 charge.<\/li>\n<\/ul>\n\n\n\n<p>This results in the neutral compound <strong>Cr(C\u2082H\u2083O\u2082)\u2082<\/strong>. It is important to note that the number of acetate ions is doubled to balance the charge of chromium in its +2 oxidation state.<\/p>\n\n\n\n<p>In general, the process of writing formulas for ionic compounds involves balancing the total positive and negative charges to ensure the compound is neutral. For chromium (II) acetate, this means having two acetate ions for every chromium ion, giving us the final formula of <strong>Cr(C\u2082H\u2083O\u2082)\u2082<\/strong>.<\/p>\n\n\n\n<p>This is typical for compounds involving transition metals like chromium, which can exist in multiple oxidation states, and for which the number of anions must balance the charge of the metal cation to form a stable compound.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>What is the formula for chromium (II) acetate? The correct answer and explanation is: The formula for chromium (II) acetate is Cr(C\u2082H\u2083O\u2082)\u2082. Explanation:Chromium (II) acetate consists of chromium in the +2 oxidation state and acetate ions. The acetate ion (C\u2082H\u2083O\u2082\u207b) is a common polyatomic ion, made up of two carbon atoms, three hydrogen atoms, and [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-266722","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/266722","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=266722"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/266722\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=266722"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=266722"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=266722"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}