{"id":267096,"date":"2025-07-23T09:28:42","date_gmt":"2025-07-23T09:28:42","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=267096"},"modified":"2025-07-23T09:28:45","modified_gmt":"2025-07-23T09:28:45","slug":"write-the-oxidation-and-reduction-half-reactions-for-the-s2o3-2-h-reaction","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/07\/23\/write-the-oxidation-and-reduction-half-reactions-for-the-s2o3-2-h-reaction\/","title":{"rendered":"write the oxidation and reduction half-reactions for the S2O3 2- \/H+ reaction"},"content":{"rendered":"\n<p>write the oxidation and reduction half-reactions for the S2O3 2- \/H+ reaction.<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-0-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>In the reaction involving <strong>thiosulfate<\/strong> (S2O3\u00b2\u207b) and <strong>hydrogen ions<\/strong> (H\u207a), we can write the oxidation and reduction half-reactions separately. The reaction typically occurs in an acidic solution and is often associated with redox processes such as the reduction of thiosulfate to elemental sulfur or sulfite. Below is a breakdown of the half-reactions.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Oxidation Half-Reaction:<\/h3>\n\n\n\n<p>In the oxidation half-reaction, thiosulfate (S2O3\u00b2\u207b) loses electrons and undergoes oxidation to form sulfite (SO3\u00b2\u207b) or elemental sulfur.<\/p>\n\n\n\n<p><strong>Oxidation of thiosulfate to sulfite:<\/strong>S2O32\u2212\u2192SO32\u2212+e\u2212\\text{S}_2\\text{O}_3^{2-} \\rightarrow \\text{SO}_3^{2-} + \\text{e}^-S2\u200bO32\u2212\u200b\u2192SO32\u2212\u200b+e\u2212<\/p>\n\n\n\n<p>In this half-reaction, one of the sulfur atoms in the thiosulfate ion is oxidized, resulting in the formation of sulfite.<\/p>\n\n\n\n<p><strong>Oxidation of thiosulfate to elemental sulfur:<\/strong>S2O32\u2212\u2192S+SO32\u2212+2e\u2212\\text{S}_2\\text{O}_3^{2-} \\rightarrow \\text{S} + \\text{SO}_3^{2-} + 2e^-S2\u200bO32\u2212\u200b\u2192S+SO32\u2212\u200b+2e\u2212<\/p>\n\n\n\n<p>In this case, thiosulfate is oxidized, leading to the formation of elemental sulfur and sulfite, while two electrons are lost.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Reduction Half-Reaction:<\/h3>\n\n\n\n<p>In the reduction half-reaction, hydrogen ions (H\u207a) are reduced to form hydrogen gas (H2).2H++2e\u2212\u2192H22H^+ + 2e^- \\rightarrow H_22H++2e\u2212\u2192H2\u200b<\/p>\n\n\n\n<p>This half-reaction shows that two hydrogen ions gain two electrons to form hydrogen gas.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Overall Reaction:<\/h3>\n\n\n\n<p>When these half-reactions are combined, we get a balanced redox reaction that reflects both the oxidation of thiosulfate and the reduction of hydrogen ions:S2O32\u2212+2H+\u2192S+SO32\u2212+H2\\text{S}_2\\text{O}_3^{2-} + 2H^+ \\rightarrow \\text{S} + \\text{SO}_3^{2-} + H_2S2\u200bO32\u2212\u200b+2H+\u2192S+SO32\u2212\u200b+H2\u200b<\/p>\n\n\n\n<p>In this reaction, thiosulfate is oxidized to sulfur and sulfite, while hydrogen ions are reduced to hydrogen gas.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Summary:<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The <strong>oxidation half-reaction<\/strong> involves the loss of electrons by thiosulfate (S2O3\u00b2\u207b).<\/li>\n\n\n\n<li>The <strong>reduction half-reaction<\/strong> involves the gain of electrons by hydrogen ions (H\u207a) to form hydrogen gas (H2).<\/li>\n\n\n\n<li>The overall redox reaction involves both the oxidation of thiosulfate and the reduction of hydrogen ions.<\/li>\n<\/ul>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/07\/learnexams-banner6-1662.jpeg\" alt=\"\" class=\"wp-image-267097\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>write the oxidation and reduction half-reactions for the S2O3 2- \/H+ reaction. The Correct Answer and Explanation is: In the reaction involving thiosulfate (S2O3\u00b2\u207b) and hydrogen ions (H\u207a), we can write the oxidation and reduction half-reactions separately. The reaction typically occurs in an acidic solution and is often associated with redox processes such as the [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-267096","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/267096","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=267096"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/267096\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=267096"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=267096"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=267096"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}