{"id":267190,"date":"2025-07-23T10:24:20","date_gmt":"2025-07-23T10:24:20","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=267190"},"modified":"2025-07-23T10:24:23","modified_gmt":"2025-07-23T10:24:23","slug":"potassium-chloride-reacts-with-silver-nitrate-to-produce-solid-silver-chloride-and-potassium-nitrate-2","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/07\/23\/potassium-chloride-reacts-with-silver-nitrate-to-produce-solid-silver-chloride-and-potassium-nitrate-2\/","title":{"rendered":"Potassium chloride reacts with silver nitrate to produce solid silver chloride and potassium nitrate"},"content":{"rendered":"\n

Potassium chloride reacts with silver nitrate to produce solid silver chloride and potassium nitrate: KCl(aq) + AgNO3(aq) \u00e2\u2020\u2019 AgCl(s) + KNO3(aq) How many grams of KCl are required to react completely with 250 mL of 0.030 M AgNO3?<\/p>\n\n\n\n

The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n

To find how many grams of KCl are required to react completely with 250 mL of 0.030 M AgNO3, we need to follow these steps:<\/p>\n\n\n\n

Step 1: Write the balanced chemical equation<\/h3>\n\n\n\n

The reaction is:KCl(aq)+AgNO3(aq)\u2192AgCl(s)+KNO3(aq)\\text{KCl} (aq) + \\text{AgNO}_3 (aq) \\rightarrow \\text{AgCl} (s) + \\text{KNO}_3 (aq)KCl(aq)+AgNO3\u200b(aq)\u2192AgCl(s)+KNO3\u200b(aq)<\/p>\n\n\n\n

From this equation, you can see that 1 mole of KCl reacts with 1 mole of AgNO3.<\/p>\n\n\n\n

Step 2: Calculate the moles of AgNO3<\/h3>\n\n\n\n

We are given the volume and molarity of AgNO3:<\/p>\n\n\n\n

    \n
  • Volume of AgNO3 = 250 mL = 0.250 L<\/li>\n\n\n\n
  • Molarity of AgNO3 = 0.030 M<\/li>\n<\/ul>\n\n\n\n

    The number of moles of AgNO3 is given by the formula:moles of AgNO3=Molarity\u00d7Volume (in L)\\text{moles of AgNO}_3 = \\text{Molarity} \\times \\text{Volume (in L)}moles of AgNO3\u200b=Molarity\u00d7Volume (in L)moles of AgNO3=0.030\u2009mol\/L\u00d70.250\u2009L=0.0075\u2009mol\\text{moles of AgNO}_3 = 0.030 \\, \\text{mol\/L} \\times 0.250 \\, \\text{L} = 0.0075 \\, \\text{mol}moles of AgNO3\u200b=0.030mol\/L\u00d70.250L=0.0075mol<\/p>\n\n\n\n

    Step 3: Moles of KCl required<\/h3>\n\n\n\n

    From the balanced equation, we know that the reaction occurs in a 1:1 ratio, so the moles of KCl required will also be 0.0075 mol.<\/p>\n\n\n\n

    Step 4: Convert moles of KCl to grams<\/h3>\n\n\n\n

    Now, we need to find the mass of KCl required. The molar mass of KCl is:Molar mass of KCl=39.1\u2009g\/mol (for K)+35.5\u2009g\/mol (for Cl)=74.6\u2009g\/mol\\text{Molar mass of KCl} = 39.1 \\, \\text{g\/mol (for K)} + 35.5 \\, \\text{g\/mol (for Cl)} = 74.6 \\, \\text{g\/mol}Molar mass of KCl=39.1g\/mol (for K)+35.5g\/mol (for Cl)=74.6g\/mol<\/p>\n\n\n\n

    The mass of KCl required is:mass of KCl=moles of KCl\u00d7molar mass of KCl\\text{mass of KCl} = \\text{moles of KCl} \\times \\text{molar mass of KCl}mass of KCl=moles of KCl\u00d7molar mass of KClmass of KCl=0.0075\u2009mol\u00d774.6\u2009g\/mol=0.5595\u2009g\\text{mass of KCl} = 0.0075 \\, \\text{mol} \\times 74.6 \\, \\text{g\/mol} = 0.5595 \\, \\text{g}mass of KCl=0.0075mol\u00d774.6g\/mol=0.5595g<\/p>\n\n\n\n

    Final Answer:<\/h3>\n\n\n\n

    So, 0.56 grams<\/strong> of KCl are required to react completely with 250 mL of 0.030 M AgNO3.<\/p>\n\n\n\n

    \"\"<\/figure>\n","protected":false},"excerpt":{"rendered":"

    Potassium chloride reacts with silver nitrate to produce solid silver chloride and potassium nitrate: KCl(aq) + AgNO3(aq) \u00e2\u2020\u2019 AgCl(s) + KNO3(aq) How many grams of KCl are required to react completely with 250 mL of 0.030 M AgNO3? The Correct Answer and Explanation is: To find how many grams of KCl are required to react […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-267190","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/267190","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=267190"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/267190\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=267190"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=267190"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=267190"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}