<\/h6>\n\n\n\n
Let’s break down the reactions and deduce the structures of compounds A through F.<\/p>\n\n\n\n
Step 1: Compound A (C7H11Br) reacts with magnesium to form B (C7H11MgBr) in ether<\/strong><\/h3>\n\n\n\n\n- The reaction of A (C7H11Br)<\/strong> with magnesium in ether suggests a Grignard reagent formation<\/strong>. Grignard reagents are typically of the form R-MgBr<\/strong>, and this indicates that A is likely an alkyl bromide. The molecular formula C7H11Br<\/strong> suggests it is a bromocyclohexane derivative<\/strong> (since it contains 7 carbon atoms and one bromine atom).<\/li>\n\n\n\n
- A plausible structure for A<\/strong> is 1-bromo-3-methylcyclohexane<\/strong>. This would make sense for the Grignard reagent (B), which would be 1-methyl-3-(magnesium bromide)-cyclohexane<\/strong> (C7H11MgBr).<\/li>\n<\/ul>\n\n\n\n
Step 2: B reacts with D2O to form 1-methylcyclohexene with a deuterium atom on the methyl group<\/strong><\/h3>\n\n\n\n\n- The Grignard reagent B (C7H11MgBr)<\/strong> reacts with D2O<\/strong> (heavy water), which leads to the formation of a deuterated product<\/strong>. Since the deuterium is incorporated into the methyl group<\/strong>, we can infer that B<\/strong> undergoes elimination<\/strong> (a common reaction with Grignard reagents when treated with water or D2O).<\/li>\n\n\n\n
- This leads to the formation of 1-methylcyclohexene<\/strong> with D<\/strong> on the methyl group. Therefore, C<\/strong> is 1-methylcyclohexene<\/strong>, and the deuterium is at the C1<\/strong> position in the methyl group (forming CH2D<\/strong>).<\/li>\n<\/ul>\n\n\n\n
Step 3: B reacts with acetone (CH3COCH3) to give D (C10H18O)<\/strong><\/h3>\n\n\n\n\n- The reaction of B<\/strong> with acetone<\/strong> suggests a nucleophilic addition<\/strong> to acetone, forming a tert-butyl<\/strong> group (since the Grignard reagent is a strong nucleophile). This results in the formation of a new carbon-carbon bond between C7H11<\/strong> and CH3COCH3<\/strong>, giving C10H18O<\/strong>.<\/li>\n\n\n\n
- The structure of D<\/strong> is likely 2-methyl-1-(1-methylcyclohexyl)-propan-2-ol<\/strong>, which fits the molecular formula C10H18O<\/strong>.<\/li>\n<\/ul>\n\n\n\n
Step 4: Heating D with concentrated H2SO4 gives E (C10H16)<\/strong><\/h3>\n\n\n\n\n- The treatment of D<\/strong> with concentrated H2SO4<\/strong> suggests an elimination<\/strong> reaction, forming a double bond. The molecular formula for E<\/strong> is C10H16<\/strong>, which implies the loss of H2O<\/strong> from the alcohol group of D<\/strong>, forming an alkene.<\/li>\n\n\n\n
- This suggests that E<\/strong> is likely 1-methylcyclohexene<\/strong>, derived by eliminating water from D<\/strong>.<\/li>\n<\/ul>\n\n\n\n
Step 5: E reacts with Br2 to form F (C10H16Br4)<\/strong><\/h3>\n\n\n\n\n- The addition of Br2<\/strong> to E (C10H16)<\/strong> suggests that E<\/strong> is an alkene, which undergoes electrophilic addition<\/strong> with bromine, leading to the formation of F (C10H16Br4)<\/strong>.<\/li>\n\n\n\n
- This indicates that F<\/strong> is a tetrabromo derivative<\/strong> of E<\/strong>, where the addition of two equivalents of bromine occurs in a cis<\/strong> manner across the double bond, leading to F<\/strong> as a vicinal dibromide<\/strong>.<\/li>\n<\/ul>\n\n\n\n
Step 6: E undergoes hydrogenation to give isobutylcyclohexane<\/strong><\/h3>\n\n\n\n\n- The hydrogenation of E<\/strong> (C10H16) using excess H2 and a Pt catalyst<\/strong> results in the saturation of the double bond, forming isobutylcyclohexane<\/strong>.<\/li>\n\n\n\n
- This confirms that the hydrogenation<\/strong> of E<\/strong> yields a saturated product<\/strong>, which is likely isobutylcyclohexane<\/strong> with a branched isobutyl group.<\/li>\n<\/ul>\n\n\n\n
Conclusion<\/h3>\n\n\n\n\n- A<\/strong>: 1-bromo-3-methylcyclohexane<\/li>\n\n\n\n
- B<\/strong>: 1-methyl-3-(magnesium bromide)-cyclohexane (Grignard reagent)<\/li>\n\n\n\n
- C<\/strong>: 1-methylcyclohexene with a deuterium atom on the methyl group (CH2D)<\/li>\n\n\n\n
- D<\/strong>: 2-methyl-1-(1-methylcyclohexyl)-propan-2-ol<\/li>\n\n\n\n
- E<\/strong>: 1-methylcyclohexene (formed by dehydration of D)<\/li>\n\n\n\n
- F<\/strong>: Tetrabromo derivative of E (C10H16Br4)<\/li>\n<\/ul>\n\n\n\n
These reactions demonstrate the formation of a Grignard reagent, nucleophilic addition, elimination, electrophilic addition, and hydrogenation, leading to the final product.<\/p>\n\n\n\n![\"\"](\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/07\/learnexams-banner6-1678.jpeg\")
<\/figure>\n","protected":false},"excerpt":{"rendered":"Compound A (C7H11Br) is treated with magnesium in ether to give B (C7H11MgBr), which reacts violently with D2O togive 1-methylcyclohexene with a deuterium atom on the methyl group (C). Reaction of B with acetone (CH3COCH3)followed by hydrolysis gives D (C10H18O). Heating D with concentrated H2SO4 gives E (C10H16), which decolorizestwo equivalents of Br2 to give […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-267198","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/267198","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=267198"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/267198\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=267198"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=267198"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=267198"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}
Step 2: B reacts with D2O to form 1-methylcyclohexene with a deuterium atom on the methyl group<\/strong><\/h3>\n\n\n\n\n- The Grignard reagent B (C7H11MgBr)<\/strong> reacts with D2O<\/strong> (heavy water), which leads to the formation of a deuterated product<\/strong>. Since the deuterium is incorporated into the methyl group<\/strong>, we can infer that B<\/strong> undergoes elimination<\/strong> (a common reaction with Grignard reagents when treated with water or D2O).<\/li>\n\n\n\n
- This leads to the formation of 1-methylcyclohexene<\/strong> with D<\/strong> on the methyl group. Therefore, C<\/strong> is 1-methylcyclohexene<\/strong>, and the deuterium is at the C1<\/strong> position in the methyl group (forming CH2D<\/strong>).<\/li>\n<\/ul>\n\n\n\n
Step 3: B reacts with acetone (CH3COCH3) to give D (C10H18O)<\/strong><\/h3>\n\n\n\n\n- The reaction of B<\/strong> with acetone<\/strong> suggests a nucleophilic addition<\/strong> to acetone, forming a tert-butyl<\/strong> group (since the Grignard reagent is a strong nucleophile). This results in the formation of a new carbon-carbon bond between C7H11<\/strong> and CH3COCH3<\/strong>, giving C10H18O<\/strong>.<\/li>\n\n\n\n
- The structure of D<\/strong> is likely 2-methyl-1-(1-methylcyclohexyl)-propan-2-ol<\/strong>, which fits the molecular formula C10H18O<\/strong>.<\/li>\n<\/ul>\n\n\n\n
Step 4: Heating D with concentrated H2SO4 gives E (C10H16)<\/strong><\/h3>\n\n\n\n\n- The treatment of D<\/strong> with concentrated H2SO4<\/strong> suggests an elimination<\/strong> reaction, forming a double bond. The molecular formula for E<\/strong> is C10H16<\/strong>, which implies the loss of H2O<\/strong> from the alcohol group of D<\/strong>, forming an alkene.<\/li>\n\n\n\n
- This suggests that E<\/strong> is likely 1-methylcyclohexene<\/strong>, derived by eliminating water from D<\/strong>.<\/li>\n<\/ul>\n\n\n\n
Step 5: E reacts with Br2 to form F (C10H16Br4)<\/strong><\/h3>\n\n\n\n\n- The addition of Br2<\/strong> to E (C10H16)<\/strong> suggests that E<\/strong> is an alkene, which undergoes electrophilic addition<\/strong> with bromine, leading to the formation of F (C10H16Br4)<\/strong>.<\/li>\n\n\n\n
- This indicates that F<\/strong> is a tetrabromo derivative<\/strong> of E<\/strong>, where the addition of two equivalents of bromine occurs in a cis<\/strong> manner across the double bond, leading to F<\/strong> as a vicinal dibromide<\/strong>.<\/li>\n<\/ul>\n\n\n\n
Step 6: E undergoes hydrogenation to give isobutylcyclohexane<\/strong><\/h3>\n\n\n\n\n- The hydrogenation of E<\/strong> (C10H16) using excess H2 and a Pt catalyst<\/strong> results in the saturation of the double bond, forming isobutylcyclohexane<\/strong>.<\/li>\n\n\n\n
- This confirms that the hydrogenation<\/strong> of E<\/strong> yields a saturated product<\/strong>, which is likely isobutylcyclohexane<\/strong> with a branched isobutyl group.<\/li>\n<\/ul>\n\n\n\n
Conclusion<\/h3>\n\n\n\n\n- A<\/strong>: 1-bromo-3-methylcyclohexane<\/li>\n\n\n\n
- B<\/strong>: 1-methyl-3-(magnesium bromide)-cyclohexane (Grignard reagent)<\/li>\n\n\n\n
- C<\/strong>: 1-methylcyclohexene with a deuterium atom on the methyl group (CH2D)<\/li>\n\n\n\n
- D<\/strong>: 2-methyl-1-(1-methylcyclohexyl)-propan-2-ol<\/li>\n\n\n\n
- E<\/strong>: 1-methylcyclohexene (formed by dehydration of D)<\/li>\n\n\n\n
- F<\/strong>: Tetrabromo derivative of E (C10H16Br4)<\/li>\n<\/ul>\n\n\n\n
These reactions demonstrate the formation of a Grignard reagent, nucleophilic addition, elimination, electrophilic addition, and hydrogenation, leading to the final product.<\/p>\n\n\n\n<\/figure>\n","protected":false},"excerpt":{"rendered":"Compound A (C7H11Br) is treated with magnesium in ether to give B (C7H11MgBr), which reacts violently with D2O togive 1-methylcyclohexene with a deuterium atom on the methyl group (C). Reaction of B with acetone (CH3COCH3)followed by hydrolysis gives D (C10H18O). Heating D with concentrated H2SO4 gives E (C10H16), which decolorizestwo equivalents of Br2 to give […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-267198","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/267198","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=267198"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/267198\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=267198"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=267198"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=267198"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}
Step 3: B reacts with acetone (CH3COCH3) to give D (C10H18O)<\/strong><\/h3>\n\n\n\n\n- The reaction of B<\/strong> with acetone<\/strong> suggests a nucleophilic addition<\/strong> to acetone, forming a tert-butyl<\/strong> group (since the Grignard reagent is a strong nucleophile). This results in the formation of a new carbon-carbon bond between C7H11<\/strong> and CH3COCH3<\/strong>, giving C10H18O<\/strong>.<\/li>\n\n\n\n
- The structure of D<\/strong> is likely 2-methyl-1-(1-methylcyclohexyl)-propan-2-ol<\/strong>, which fits the molecular formula C10H18O<\/strong>.<\/li>\n<\/ul>\n\n\n\n
Step 4: Heating D with concentrated H2SO4 gives E (C10H16)<\/strong><\/h3>\n\n\n\n\n- The treatment of D<\/strong> with concentrated H2SO4<\/strong> suggests an elimination<\/strong> reaction, forming a double bond. The molecular formula for E<\/strong> is C10H16<\/strong>, which implies the loss of H2O<\/strong> from the alcohol group of D<\/strong>, forming an alkene.<\/li>\n\n\n\n
- This suggests that E<\/strong> is likely 1-methylcyclohexene<\/strong>, derived by eliminating water from D<\/strong>.<\/li>\n<\/ul>\n\n\n\n
Step 5: E reacts with Br2 to form F (C10H16Br4)<\/strong><\/h3>\n\n\n\n\n- The addition of Br2<\/strong> to E (C10H16)<\/strong> suggests that E<\/strong> is an alkene, which undergoes electrophilic addition<\/strong> with bromine, leading to the formation of F (C10H16Br4)<\/strong>.<\/li>\n\n\n\n
- This indicates that F<\/strong> is a tetrabromo derivative<\/strong> of E<\/strong>, where the addition of two equivalents of bromine occurs in a cis<\/strong> manner across the double bond, leading to F<\/strong> as a vicinal dibromide<\/strong>.<\/li>\n<\/ul>\n\n\n\n
Step 6: E undergoes hydrogenation to give isobutylcyclohexane<\/strong><\/h3>\n\n\n\n\n- The hydrogenation of E<\/strong> (C10H16) using excess H2 and a Pt catalyst<\/strong> results in the saturation of the double bond, forming isobutylcyclohexane<\/strong>.<\/li>\n\n\n\n
- This confirms that the hydrogenation<\/strong> of E<\/strong> yields a saturated product<\/strong>, which is likely isobutylcyclohexane<\/strong> with a branched isobutyl group.<\/li>\n<\/ul>\n\n\n\n
Conclusion<\/h3>\n\n\n\n\n- A<\/strong>: 1-bromo-3-methylcyclohexane<\/li>\n\n\n\n
- B<\/strong>: 1-methyl-3-(magnesium bromide)-cyclohexane (Grignard reagent)<\/li>\n\n\n\n
- C<\/strong>: 1-methylcyclohexene with a deuterium atom on the methyl group (CH2D)<\/li>\n\n\n\n
- D<\/strong>: 2-methyl-1-(1-methylcyclohexyl)-propan-2-ol<\/li>\n\n\n\n
- E<\/strong>: 1-methylcyclohexene (formed by dehydration of D)<\/li>\n\n\n\n
- F<\/strong>: Tetrabromo derivative of E (C10H16Br4)<\/li>\n<\/ul>\n\n\n\n
These reactions demonstrate the formation of a Grignard reagent, nucleophilic addition, elimination, electrophilic addition, and hydrogenation, leading to the final product.<\/p>\n\n\n\n<\/figure>\n","protected":false},"excerpt":{"rendered":"Compound A (C7H11Br) is treated with magnesium in ether to give B (C7H11MgBr), which reacts violently with D2O togive 1-methylcyclohexene with a deuterium atom on the methyl group (C). Reaction of B with acetone (CH3COCH3)followed by hydrolysis gives D (C10H18O). Heating D with concentrated H2SO4 gives E (C10H16), which decolorizestwo equivalents of Br2 to give […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-267198","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/267198","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=267198"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/267198\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=267198"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=267198"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=267198"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}
Step 4: Heating D with concentrated H2SO4 gives E (C10H16)<\/strong><\/h3>\n\n\n\n\n- The treatment of D<\/strong> with concentrated H2SO4<\/strong> suggests an elimination<\/strong> reaction, forming a double bond. The molecular formula for E<\/strong> is C10H16<\/strong>, which implies the loss of H2O<\/strong> from the alcohol group of D<\/strong>, forming an alkene.<\/li>\n\n\n\n
- This suggests that E<\/strong> is likely 1-methylcyclohexene<\/strong>, derived by eliminating water from D<\/strong>.<\/li>\n<\/ul>\n\n\n\n
Step 5: E reacts with Br2 to form F (C10H16Br4)<\/strong><\/h3>\n\n\n\n\n- The addition of Br2<\/strong> to E (C10H16)<\/strong> suggests that E<\/strong> is an alkene, which undergoes electrophilic addition<\/strong> with bromine, leading to the formation of F (C10H16Br4)<\/strong>.<\/li>\n\n\n\n
- This indicates that F<\/strong> is a tetrabromo derivative<\/strong> of E<\/strong>, where the addition of two equivalents of bromine occurs in a cis<\/strong> manner across the double bond, leading to F<\/strong> as a vicinal dibromide<\/strong>.<\/li>\n<\/ul>\n\n\n\n
Step 6: E undergoes hydrogenation to give isobutylcyclohexane<\/strong><\/h3>\n\n\n\n\n- The hydrogenation of E<\/strong> (C10H16) using excess H2 and a Pt catalyst<\/strong> results in the saturation of the double bond, forming isobutylcyclohexane<\/strong>.<\/li>\n\n\n\n
- This confirms that the hydrogenation<\/strong> of E<\/strong> yields a saturated product<\/strong>, which is likely isobutylcyclohexane<\/strong> with a branched isobutyl group.<\/li>\n<\/ul>\n\n\n\n
Conclusion<\/h3>\n\n\n\n\n- A<\/strong>: 1-bromo-3-methylcyclohexane<\/li>\n\n\n\n
- B<\/strong>: 1-methyl-3-(magnesium bromide)-cyclohexane (Grignard reagent)<\/li>\n\n\n\n
- C<\/strong>: 1-methylcyclohexene with a deuterium atom on the methyl group (CH2D)<\/li>\n\n\n\n
- D<\/strong>: 2-methyl-1-(1-methylcyclohexyl)-propan-2-ol<\/li>\n\n\n\n
- E<\/strong>: 1-methylcyclohexene (formed by dehydration of D)<\/li>\n\n\n\n
- F<\/strong>: Tetrabromo derivative of E (C10H16Br4)<\/li>\n<\/ul>\n\n\n\n
These reactions demonstrate the formation of a Grignard reagent, nucleophilic addition, elimination, electrophilic addition, and hydrogenation, leading to the final product.<\/p>\n\n\n\n<\/figure>\n","protected":false},"excerpt":{"rendered":"Compound A (C7H11Br) is treated with magnesium in ether to give B (C7H11MgBr), which reacts violently with D2O togive 1-methylcyclohexene with a deuterium atom on the methyl group (C). Reaction of B with acetone (CH3COCH3)followed by hydrolysis gives D (C10H18O). Heating D with concentrated H2SO4 gives E (C10H16), which decolorizestwo equivalents of Br2 to give […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-267198","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/267198","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=267198"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/267198\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=267198"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=267198"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=267198"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}
Step 5: E reacts with Br2 to form F (C10H16Br4)<\/strong><\/h3>\n\n\n\n\n- The addition of Br2<\/strong> to E (C10H16)<\/strong> suggests that E<\/strong> is an alkene, which undergoes electrophilic addition<\/strong> with bromine, leading to the formation of F (C10H16Br4)<\/strong>.<\/li>\n\n\n\n
- This indicates that F<\/strong> is a tetrabromo derivative<\/strong> of E<\/strong>, where the addition of two equivalents of bromine occurs in a cis<\/strong> manner across the double bond, leading to F<\/strong> as a vicinal dibromide<\/strong>.<\/li>\n<\/ul>\n\n\n\n
Step 6: E undergoes hydrogenation to give isobutylcyclohexane<\/strong><\/h3>\n\n\n\n\n- The hydrogenation of E<\/strong> (C10H16) using excess H2 and a Pt catalyst<\/strong> results in the saturation of the double bond, forming isobutylcyclohexane<\/strong>.<\/li>\n\n\n\n
- This confirms that the hydrogenation<\/strong> of E<\/strong> yields a saturated product<\/strong>, which is likely isobutylcyclohexane<\/strong> with a branched isobutyl group.<\/li>\n<\/ul>\n\n\n\n
Conclusion<\/h3>\n\n\n\n\n- A<\/strong>: 1-bromo-3-methylcyclohexane<\/li>\n\n\n\n
- B<\/strong>: 1-methyl-3-(magnesium bromide)-cyclohexane (Grignard reagent)<\/li>\n\n\n\n
- C<\/strong>: 1-methylcyclohexene with a deuterium atom on the methyl group (CH2D)<\/li>\n\n\n\n
- D<\/strong>: 2-methyl-1-(1-methylcyclohexyl)-propan-2-ol<\/li>\n\n\n\n
- E<\/strong>: 1-methylcyclohexene (formed by dehydration of D)<\/li>\n\n\n\n
- F<\/strong>: Tetrabromo derivative of E (C10H16Br4)<\/li>\n<\/ul>\n\n\n\n
These reactions demonstrate the formation of a Grignard reagent, nucleophilic addition, elimination, electrophilic addition, and hydrogenation, leading to the final product.<\/p>\n\n\n\n<\/figure>\n","protected":false},"excerpt":{"rendered":"Compound A (C7H11Br) is treated with magnesium in ether to give B (C7H11MgBr), which reacts violently with D2O togive 1-methylcyclohexene with a deuterium atom on the methyl group (C). Reaction of B with acetone (CH3COCH3)followed by hydrolysis gives D (C10H18O). Heating D with concentrated H2SO4 gives E (C10H16), which decolorizestwo equivalents of Br2 to give […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-267198","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/267198","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=267198"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/267198\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=267198"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=267198"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=267198"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}
Step 6: E undergoes hydrogenation to give isobutylcyclohexane<\/strong><\/h3>\n\n\n\n\n- The hydrogenation of E<\/strong> (C10H16) using excess H2 and a Pt catalyst<\/strong> results in the saturation of the double bond, forming isobutylcyclohexane<\/strong>.<\/li>\n\n\n\n
- This confirms that the hydrogenation<\/strong> of E<\/strong> yields a saturated product<\/strong>, which is likely isobutylcyclohexane<\/strong> with a branched isobutyl group.<\/li>\n<\/ul>\n\n\n\n
Conclusion<\/h3>\n\n\n\n\n- A<\/strong>: 1-bromo-3-methylcyclohexane<\/li>\n\n\n\n
- B<\/strong>: 1-methyl-3-(magnesium bromide)-cyclohexane (Grignard reagent)<\/li>\n\n\n\n
- C<\/strong>: 1-methylcyclohexene with a deuterium atom on the methyl group (CH2D)<\/li>\n\n\n\n
- D<\/strong>: 2-methyl-1-(1-methylcyclohexyl)-propan-2-ol<\/li>\n\n\n\n
- E<\/strong>: 1-methylcyclohexene (formed by dehydration of D)<\/li>\n\n\n\n
- F<\/strong>: Tetrabromo derivative of E (C10H16Br4)<\/li>\n<\/ul>\n\n\n\n
These reactions demonstrate the formation of a Grignard reagent, nucleophilic addition, elimination, electrophilic addition, and hydrogenation, leading to the final product.<\/p>\n\n\n\n<\/figure>\n","protected":false},"excerpt":{"rendered":"Compound A (C7H11Br) is treated with magnesium in ether to give B (C7H11MgBr), which reacts violently with D2O togive 1-methylcyclohexene with a deuterium atom on the methyl group (C). Reaction of B with acetone (CH3COCH3)followed by hydrolysis gives D (C10H18O). Heating D with concentrated H2SO4 gives E (C10H16), which decolorizestwo equivalents of Br2 to give […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-267198","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/267198","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=267198"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/267198\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=267198"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=267198"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=267198"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}
Conclusion<\/h3>\n\n\n\n\n- A<\/strong>: 1-bromo-3-methylcyclohexane<\/li>\n\n\n\n
- B<\/strong>: 1-methyl-3-(magnesium bromide)-cyclohexane (Grignard reagent)<\/li>\n\n\n\n
- C<\/strong>: 1-methylcyclohexene with a deuterium atom on the methyl group (CH2D)<\/li>\n\n\n\n
- D<\/strong>: 2-methyl-1-(1-methylcyclohexyl)-propan-2-ol<\/li>\n\n\n\n
- E<\/strong>: 1-methylcyclohexene (formed by dehydration of D)<\/li>\n\n\n\n
- F<\/strong>: Tetrabromo derivative of E (C10H16Br4)<\/li>\n<\/ul>\n\n\n\n
These reactions demonstrate the formation of a Grignard reagent, nucleophilic addition, elimination, electrophilic addition, and hydrogenation, leading to the final product.<\/p>\n\n\n\n<\/figure>\n","protected":false},"excerpt":{"rendered":"Compound A (C7H11Br) is treated with magnesium in ether to give B (C7H11MgBr), which reacts violently with D2O togive 1-methylcyclohexene with a deuterium atom on the methyl group (C). Reaction of B with acetone (CH3COCH3)followed by hydrolysis gives D (C10H18O). Heating D with concentrated H2SO4 gives E (C10H16), which decolorizestwo equivalents of Br2 to give […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-267198","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/267198","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=267198"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/267198\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=267198"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=267198"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=267198"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}
These reactions demonstrate the formation of a Grignard reagent, nucleophilic addition, elimination, electrophilic addition, and hydrogenation, leading to the final product.<\/p>\n\n\n\n Compound A (C7H11Br) is treated with magnesium in ether to give B (C7H11MgBr), which reacts violently with D2O togive 1-methylcyclohexene with a deuterium atom on the methyl group (C). Reaction of B with acetone (CH3COCH3)followed by hydrolysis gives D (C10H18O). Heating D with concentrated H2SO4 gives E (C10H16), which decolorizestwo equivalents of Br2 to give […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-267198","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/267198","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=267198"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/267198\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=267198"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=267198"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=267198"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}<\/figure>\n","protected":false},"excerpt":{"rendered":"