{"id":267979,"date":"2025-07-23T18:18:54","date_gmt":"2025-07-23T18:18:54","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=267979"},"modified":"2025-07-23T18:18:58","modified_gmt":"2025-07-23T18:18:58","slug":"draw-the-mechainsm-for-the-reaction-2methyl-1-butene-h2so4-in-water-solution-2-methyl-2-butanol-sulfric-acid-water","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/07\/23\/draw-the-mechainsm-for-the-reaction-2methyl-1-butene-h2so4-in-water-solution-2-methyl-2-butanol-sulfric-acid-water\/","title":{"rendered":"Draw the mechainsm for the reaction (2methyl-1-butene +H2SO4 )in water solution –>2-methyl-2-butanol +sulfric acid+ water"},"content":{"rendered":"\n

Draw the mechainsm for the reaction (2methyl-1-butene +H2SO4 )in water solution –>2-methyl-2-butanol +sulfric acid+ water<\/p>\n\n\n\n

The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n

The reaction you’re asking about is an example of an electrophilic addition reaction, where 2-methyl-1-butene reacts with sulfuric acid (H\u2082SO\u2084) in water. The products are 2-methyl-2-butanol, sulfuric acid, and water. Here’s the mechanism broken down step-by-step:<\/p>\n\n\n\n

    \n
  1. Protonation of the Alkene<\/strong>:\n
      \n
    • The double bond in 2-methyl-1-butene is nucleophilic and attacks the proton (H\u207a) from sulfuric acid. This leads to the formation of a carbocation intermediate.<\/li>\n\n\n\n
    • Since the carbocation will be more stable if formed at the more substituted carbon (the carbon next to the CH\u2083 group), the proton will add to the carbon atom that is less substituted (C1), forming a carbocation at the C2 position.<\/li>\n<\/ul>\n<\/li>\n\n\n\n
    • Carbocation Formation<\/strong>:\n
        \n
      • The resulting carbocation (on C2) is a secondary carbocation and can undergo rearrangement to form a more stable carbocation. In this case, there is no rearrangement, as the C2 carbocation is already relatively stable.<\/li>\n<\/ul>\n<\/li>\n\n\n\n
      • Nucleophilic Attack by Water<\/strong>:\n
          \n
        • Water, being a nucleophile, attacks the carbocation formed at C2. The oxygen atom of water donates a lone pair of electrons to the carbocation, forming an oxonium ion (C2-OH\u2082\u207a).<\/li>\n<\/ul>\n<\/li>\n\n\n\n
        • Deprotonation<\/strong>:\n
            \n
          • The oxonium ion formed in step 3 is protonated, and this proton is lost to form the final product: 2-methyl-2-butanol<\/strong>.<\/li>\n<\/ul>\n<\/li>\n\n\n\n
          • Sulfuric Acid Regeneration<\/strong>:\n
              \n
            • The proton that was initially added to the alkene is now released during the deprotonation step. Therefore, the sulfuric acid catalyst is regenerated.<\/li>\n<\/ul>\n<\/li>\n<\/ol>\n\n\n\n

              Reaction Summary:<\/h3>\n\n\n\n

              The overall reaction involves electrophilic addition of H\u207a to 2-methyl-1-butene, followed by nucleophilic attack by water, leading to the formation of 2-methyl-2-butanol. This reaction also demonstrates the catalytic role of sulfuric acid, which is regenerated at the end of the reaction.<\/p>\n\n\n\n

              \"\"<\/figure>\n","protected":false},"excerpt":{"rendered":"

              Draw the mechainsm for the reaction (2methyl-1-butene +H2SO4 )in water solution –>2-methyl-2-butanol +sulfric acid+ water The Correct Answer and Explanation is: The reaction you’re asking about is an example of an electrophilic addition reaction, where 2-methyl-1-butene reacts with sulfuric acid (H\u2082SO\u2084) in water. The products are 2-methyl-2-butanol, sulfuric acid, and water. Here’s the mechanism broken […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-267979","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/267979","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=267979"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/267979\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=267979"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=267979"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=267979"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}