{"id":268205,"date":"2025-07-24T01:47:41","date_gmt":"2025-07-24T01:47:41","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=268205"},"modified":"2025-07-24T01:47:43","modified_gmt":"2025-07-24T01:47:43","slug":"the-molecular-mass-of-sodium-oxide-na2o-is","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/07\/24\/the-molecular-mass-of-sodium-oxide-na2o-is\/","title":{"rendered":"The molecular mass of sodium oxide (Na2O) is"},"content":{"rendered":"\n<p>The molecular mass of sodium oxide (Na2O) is A. 61.97894. B. 38.98917. C. 22.98977. D. 45.97954<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-0-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>The correct answer is <strong>A. 61.97894<\/strong>.<\/p>\n\n\n\n<p>To calculate the molecular mass of sodium oxide (Na2O), we need to add the atomic masses of the elements that make up the compound. Sodium oxide consists of two sodium (Na) atoms and one oxygen (O) atom.<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Sodium (Na)<\/strong> has an atomic mass of approximately 22.98977 g\/mol.<\/li>\n\n\n\n<li><strong>Oxygen (O)<\/strong> has an atomic mass of approximately 15.9994 g\/mol.<\/li>\n<\/ol>\n\n\n\n<p>Now, we multiply the atomic masses by the number of atoms of each element in Na2O:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>For sodium:<br>2\u00d722.98977=45.97954\u2009g\/mol2 \\times 22.98977 = 45.97954 \\, \\text{g\/mol}2\u00d722.98977=45.97954g\/mol<\/li>\n\n\n\n<li>For oxygen:<br>1\u00d715.9994=15.9994\u2009g\/mol1 \\times 15.9994 = 15.9994 \\, \\text{g\/mol}1\u00d715.9994=15.9994g\/mol<\/li>\n<\/ul>\n\n\n\n<p>Finally, we sum these values to get the molecular mass of sodium oxide:45.97954\u2009g\/mol+15.9994\u2009g\/mol=61.97894\u2009g\/mol45.97954 \\, \\text{g\/mol} + 15.9994 \\, \\text{g\/mol} = 61.97894 \\, \\text{g\/mol}45.97954g\/mol+15.9994g\/mol=61.97894g\/mol<\/p>\n\n\n\n<p>Thus, the molecular mass of Na2O is <strong>61.97894 g\/mol<\/strong>, and option <strong>A<\/strong> is the correct answer.<\/p>\n\n\n\n<p>In chemistry, understanding molecular mass is crucial for stoichiometric calculations, such as converting between moles and grams in chemical reactions. The molecular mass allows chemists to quantify substances and predict how they will interact in chemical processes.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/07\/learnexams-banner6-1762.jpeg\" alt=\"\" class=\"wp-image-268206\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>The molecular mass of sodium oxide (Na2O) is A. 61.97894. B. 38.98917. C. 22.98977. D. 45.97954 The Correct Answer and Explanation is: The correct answer is A. 61.97894. To calculate the molecular mass of sodium oxide (Na2O), we need to add the atomic masses of the elements that make up the compound. Sodium oxide consists [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-268205","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/268205","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=268205"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/268205\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=268205"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=268205"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=268205"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}