{"id":269168,"date":"2025-07-24T11:18:58","date_gmt":"2025-07-24T11:18:58","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=269168"},"modified":"2025-07-24T11:19:00","modified_gmt":"2025-07-24T11:19:00","slug":"what-is-the-stoichiometric-factor-between-n","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/07\/24\/what-is-the-stoichiometric-factor-between-n\/","title":{"rendered":"What is the stoichiometric factor between N"},"content":{"rendered":"\n

What is the stoichiometric factor between N? and NO in the following balanced chemical equation? N? + O? ? 2NO Select the correct answer below: 1 N? : 2 NO 1 N? : 1 NO 2 N? : 1 NO 2 N? : 2 NO<\/p>\n\n\n\n

The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n

The balanced chemical equation for the reaction between nitrogen and oxygen to form nitrogen monoxide (NO) is:<\/p>\n\n\n\n

N2+O2\u21922NON_2 + O_2 \\rightarrow 2NON2\u200b+O2\u200b\u21922NO<\/p>\n\n\n\n

To determine the stoichiometric factor between N2N_2N2\u200b (nitrogen) and NONONO (nitrogen monoxide), we look at the coefficients in the balanced equation.<\/p>\n\n\n\n

    \n
  1. The coefficient of N2N_2N2\u200b is 1.<\/li>\n\n\n\n
  2. The coefficient of NONONO is 2.<\/li>\n<\/ol>\n\n\n\n

    This tells us that for every 1 mole of N2N_2N2\u200b, 2 moles of NONONO are produced. Therefore, the stoichiometric factor between N2N_2N2\u200b and NONONO is 1:2<\/strong>.<\/p>\n\n\n\n

    Explanation:<\/h3>\n\n\n\n

    The stoichiometric factor in a chemical reaction represents the ratio in which the reactants and products combine or are produced. It is derived directly from the coefficients in the balanced chemical equation.<\/p>\n\n\n\n

    For example, if you start with 1 mole of N2N_2N2\u200b, the equation tells us that 2 moles of NONONO will be produced, meaning the ratio of N2N_2N2\u200b to NONONO is 1:2. Conversely, if you had 2 moles of NONONO, you would need 1 mole of N2N_2N2\u200b to react completely.<\/p>\n\n\n\n

    Understanding stoichiometric factors is crucial for performing mole-to-mole conversions in chemical calculations. For instance, if you were given a certain amount of nitrogen and wanted to know how much nitrogen monoxide would be produced, you’d multiply the number of moles of N2N_2N2\u200b by the stoichiometric factor (1 mole of N2N_2N2\u200b produces 2 moles of NONONO).<\/p>\n\n\n\n

    Thus, the correct answer is: 1 N\u2082 : 2 NO<\/strong>.<\/p>\n\n\n\n

    \"\"<\/figure>\n","protected":false},"excerpt":{"rendered":"

    What is the stoichiometric factor between N? and NO in the following balanced chemical equation? N? + O? ? 2NO Select the correct answer below: 1 N? : 2 NO 1 N? : 1 NO 2 N? : 1 NO 2 N? : 2 NO The Correct Answer and Explanation is: The balanced chemical equation […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-269168","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/269168","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=269168"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/269168\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=269168"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=269168"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=269168"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}