Let’s calculate the molar masses for each of the given compounds. We’ll sum the atomic masses of the individual elements in each formula.<\/p>\n\n\n\n
BeCl2 (Beryllium chloride):<\/p>\n\n\n\n
Atomic mass of Be = 9.012 g\/mol<\/p>\n\n\n\n
Atomic mass of Cl = 35.45 g\/mol
Molar mass = (1 \u00d7 9.012) + (2 \u00d7 35.45) = 9.012 + 70.90 = 79.912 g\/mol<\/p>\n\n\n\n
FeCl3 (Iron(III) chloride):<\/p>\n\n\n\n
Atomic mass of Fe = 55.85 g\/mol<\/p>\n\n\n\n
Atomic mass of Cl = 35.45 g\/mol
Molar mass = (1 \u00d7 55.85) + (3 \u00d7 35.45) = 55.85 + 106.35 = 162.20 g\/mol<\/p>\n\n\n\n
CCl2F2 (Dichlorodifluoromethane):<\/p>\n\n\n\n
Atomic mass of C = 12.01 g\/mol<\/p>\n\n\n\n
Atomic mass of Cl = 35.45 g\/mol<\/p>\n\n\n\n
Atomic mass of F = 18.998 g\/mol
Molar mass = (1 \u00d7 12.01) + (2 \u00d7 35.45) + (2 \u00d7 18.998) = 12.01 + 70.90 + 37.996 = 120.906 g\/mol<\/p>\n\n\n\n
Mg(OH)2 (Magnesium hydroxide):<\/p>\n\n\n\n
Atomic mass of Mg = 24.305 g\/mol<\/p>\n\n\n\n
Atomic mass of O = 16.00 g\/mol<\/p>\n\n\n\n
Atomic mass of H = 1.008 g\/mol
Molar mass = (1 \u00d7 24.305) + (2 \u00d7 16.00) + (2 \u00d7 1.008) = 24.305 + 32.00 + 2.016 = 58.321 g\/mol<\/p>\n\n\n\n
UF6 (Uranium hexafluoride):<\/p>\n\n\n\n
Atomic mass of U = 238.03 g\/mol<\/p>\n\n\n\n
Atomic mass of F = 18.998 g\/mol
Molar mass = (1 \u00d7 238.03) + (6 \u00d7 18.998) = 238.03 + 113.988 = 352.018 g\/mol<\/p>\n\n\n\n
H3PO4 (Phosphoric acid):<\/p>\n\n\n\n
Atomic mass of H = 1.008 g\/mol<\/p>\n\n\n\n
Atomic mass of P = 30.974 g\/mol<\/p>\n\n\n\n
Atomic mass of O = 16.00 g\/mol
Molar mass = (3 \u00d7 1.008) + (1 \u00d7 30.974) + (4 \u00d7 16.00) = 3.024 + 30.974 + 64.00 = 98.998 g\/mol<\/p>\n\n\n\n
(NH4)2SO4 (Ammonium sulfate):<\/p>\n\n\n\n
Atomic mass of N = 14.007 g\/mol<\/p>\n\n\n\n
Atomic mass of H = 1.008 g\/mol<\/p>\n\n\n\n
Atomic mass of S = 32.06 g\/mol<\/p>\n\n\n\n
Atomic mass of O = 16.00 g\/mol
Molar mass = (2 \u00d7 (1 \u00d7 14.007 + 4 \u00d7 1.008)) + (1 \u00d7 32.06) + (4 \u00d7 16.00) = 56.028 + 32.06 + 64.00 = 152.088 g\/mol<\/p>\n\n\n\n
CH3COOH (Acetic acid):<\/p>\n\n\n\n
Atomic mass of C = 12.01 g\/mol<\/p>\n\n\n\n
Atomic mass of H = 1.008 g\/mol<\/p>\n\n\n\n
Atomic mass of O = 16.00 g\/mol
Molar mass = (2 \u00d7 12.01) + (4 \u00d7 1.008) + (2 \u00d7 16.00) = 24.02 + 4.032 + 32.00 = 60.052 g\/mol<\/p>\n\n\n\n
Pb(NO3)2 (Lead(II) nitrate):<\/p>\n\n\n\n
Atomic mass of Pb = 207.2 g\/mol<\/p>\n\n\n\n
Atomic mass of N = 14.007 g\/mol<\/p>\n\n\n\n
Atomic mass of O = 16.00 g\/mol
Molar mass = (1 \u00d7 207.2) + (2 \u00d7 (1 \u00d7 14.007 + 3 \u00d7 16.00)) = 207.2 + 2 \u00d7 (14.007 + 48.00) = 207.2 + 124.028 = 331.228 g\/mol<\/p>\n\n\n\n
Ga2(SO3)3 (Gallium(III) sulfite):<\/p>\n\n\n\n
Atomic mass of Ga = 69.723 g\/mol<\/p>\n\n\n\n
Atomic mass of S = 32.06 g\/mol<\/p>\n\n\n\n
Atomic mass of O = 16.00 g\/mol
Molar mass = (2 \u00d7 69.723) + (3 \u00d7 (1 \u00d7 32.06 + 3 \u00d7 16.00)) = 139.446 + 3 \u00d7 (32.06 + 48.00) = 139.446 + 3 \u00d7 80.06 = 139.446 + 240.18 = 379.626 g\/mol<\/p>\n\n\n\n
Explanation: Calculate the formula (molar) masses of the following chemicals: 1) BeCl2 2) FeCl3 3) CCl2F2 4) Mg(OH)2 5) UF6 6) H3PO4 7) (NH4)2SO4 8) CH3COOH 9) Pb(NO3)2 10) Ga2(SO3)3 The Correct Answer and Explanation is: Let’s calculate the molar masses for each of the given compounds. We’ll sum the atomic masses of the individual elements […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-270431","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/270431","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=270431"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/270431\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=270431"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=270431"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=270431"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}
To calculate the molar mass of each compound, you multiply the atomic mass of each element by the number of atoms of that element in the compound’s formula. Then, sum these values for all elements in the compound. The molar mass is essentially the mass of one mole of that compound, and it is expressed in grams per mole (g\/mol). This value is crucial in stoichiometry, where you need to convert between moles, mass, and other quantities.<\/p>\n\n\n\n![\"\"](\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/07\/learnexams-banner6-1952.jpeg\")
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