{"id":278266,"date":"2025-08-02T01:48:35","date_gmt":"2025-08-02T01:48:35","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=278266"},"modified":"2025-08-02T01:48:37","modified_gmt":"2025-08-02T01:48:37","slug":"working-with-time-cards","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/08\/02\/working-with-time-cards\/","title":{"rendered":"\u00a0Working with Time Cards"},"content":{"rendered":"\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/08\/image-98.png\" alt=\"\" class=\"wp-image-278267\"\/><\/figure>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>Based on the statistical tools shown, the correct answer to a typical problem on this page would be a probability found using a z-score. For an illustrative example where a test has a mean of 80 and a standard deviation of 5, the probability of scoring less than 87 is&nbsp;<strong>0.9192<\/strong>.<\/p>\n\n\n\n<p><strong>Explanation<\/strong><\/p>\n\n\n\n<p>Unfortunately, the specific question on the provided document is unreadable due to the image quality. However, the page contains all the necessary components for solving a statistics problem involving a normal distribution. These components are the z-score formula and a standard normal distribution table, also known as a z-table. I will explain the process using a common type of problem this page is designed to solve.<\/p>\n\n\n\n<p>The purpose of a z-score is to standardize a data point. The formula z = (x &#8211; \u03bc) \/ \u03c3 transforms a value (x) from any normal distribution into a standard score. This score indicates how many standard deviations the value is from its population mean (\u03bc). Once a z-score is calculated, it can be used with the standard normal distribution, which has a mean of 0 and a standard deviation of 1.<\/p>\n\n\n\n<p>The large table connects a z-score to its cumulative probability. This probability is the area under the standard normal curve to the left of that z-score, representing the proportion of all data that falls below that value.<\/p>\n\n\n\n<p>Let&#8217;s use a hypothetical example. Suppose test scores are normally distributed with a mean (\u03bc) of 80 and a standard deviation (\u03c3) of 5. We want to find the probability a student scores less than 87.<\/p>\n\n\n\n<p>First, we calculate the z-score for x = 87:<br>z = (87 &#8211; 80) \/ 5 = 7 \/ 5 = 1.40<\/p>\n\n\n\n<p>Next, we look up this z-score in the table. We find the row for 1.4 and the column for .00. The number where they intersect is 0.9192.<\/p>\n\n\n\n<p>This means there is a 0.9192 probability, or a 91.92% chance, that a randomly selected student will score less than 87.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/08\/learnexams-banner4-24.jpeg\" alt=\"\" class=\"wp-image-278268\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>The Correct Answer and Explanation is: Based on the statistical tools shown, the correct answer to a typical problem on this page would be a probability found using a z-score. For an illustrative example where a test has a mean of 80 and a standard deviation of 5, the probability of scoring less than 87 [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-278266","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/278266","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=278266"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/278266\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=278266"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=278266"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=278266"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}