{"id":278442,"date":"2025-08-05T11:30:03","date_gmt":"2025-08-05T11:30:03","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=278442"},"modified":"2025-08-05T11:30:15","modified_gmt":"2025-08-05T11:30:15","slug":"the-first-term-in-this-number-pattern-is-7-2","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/08\/05\/the-first-term-in-this-number-pattern-is-7-2\/","title":{"rendered":"The first term in this number pattern is 7"},"content":{"rendered":"\n
\"\"<\/figure>\n\n\n\n

The Correct Answer and Explanation is:<\/mark><\/strong><\/em><\/p>\n\n\n\n

The eighth term in this pattern is 21<\/strong>.<\/p>\n\n\n\n

To find the eighth term in the sequence 7, 12, 10, 15, 13, …, we must first identify the underlying rule that governs the progression of the numbers. This is not a simple arithmetic sequence, where a constant number is added or subtracted, nor is it a geometric sequence where a constant number is multiplied or divided. Instead, it follows a more complex, alternating pattern.<\/p>\n\n\n\n

Let’s examine the operations between each consecutive term. To get from the first term, 7, to the second term, 12, we add 5 (7 + 5 = 12). To get from the second term, 12, to the third term, 10, we subtract 2 (12 – 2 = 10). To get from the third term, 10, to the fourth term, 15, we again add 5 (10 + 5 = 15). Finally, to get from the fourth term, 15, to the fifth term, 13, we again subtract 2 (15 – 2 = 13).<\/p>\n\n\n\n

This reveals a consistent, repeating rule: the pattern alternates between adding 5 to one term and then subtracting 2 from the next. We can use this established rule to continue the sequence and determine the subsequent terms until we reach the eighth position.<\/p>\n\n\n\n

We are given the first five terms: 7, 12, 10, 15, 13. The last operation performed was subtracting 2. Therefore, to find the sixth term, we must apply the next operation in the pattern, which is adding 5.<\/p>\n\n\n\n