{"id":279787,"date":"2025-08-04T10:38:07","date_gmt":"2025-08-04T10:38:07","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=279787"},"modified":"2025-08-04T10:38:09","modified_gmt":"2025-08-04T10:38:09","slug":"sid-trick-titrated-a-15-0-ml-aliquot-of-juice","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/08\/04\/sid-trick-titrated-a-15-0-ml-aliquot-of-juice\/","title":{"rendered":"Sid Trick titrated a 15.0 mL aliquot of juice."},"content":{"rendered":"\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/08\/image-353.png\" alt=\"\" class=\"wp-image-279788\"\/><\/figure>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-0-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p><strong>Answer:<\/strong><br>The amount of citric acid in the aliquot is&nbsp;<strong>0.117 grams<\/strong>.<br>The concentration of citric acid is&nbsp;<strong>7.80 mg per mL of juice<\/strong>.<\/p>\n\n\n\n<p><strong>Explanation:<\/strong><\/p>\n\n\n\n<p>This problem is solved using stoichiometry, which relates the quantities of reactants and products in a chemical reaction. The goal is to work from the known information about the titrant, sodium hydroxide (NaOH), to find the unknown quantity of the analyte, citric acid (H\u2083C\u2086H\u2085O\u2087).<\/p>\n\n\n\n<p>First, we determine the moles of NaOH used to reach the equivalence point. The volume of NaOH must be converted from milliliters to liters (18.25 mL = 0.01825 L). We then use the molarity formula:<\/p>\n\n\n\n<p>Moles = Molarity \u00d7 Volume<br>Moles of NaOH = 0.0998 mol\/L \u00d7 0.01825 L = 0.001821 moles of NaOH<\/p>\n\n\n\n<p>Next, we use the balanced chemical equation to find the mole ratio between NaOH and citric acid. The equation shows that 3 moles of NaOH react with 1 mole of citric acid. This 3:1 ratio allows us to calculate the moles of citric acid present in the juice aliquot:<\/p>\n\n\n\n<p>Moles of H\u2083C\u2086H\u2085O\u2087 = 0.001821 mol NaOH \u00d7 (1 mol H\u2083C\u2086H\u2085O\u2087 \/ 3 mol NaOH) = 0.000607 moles of H\u2083C\u2086H\u2085O\u2087<\/p>\n\n\n\n<p>To answer the first question, we convert these moles of citric acid into grams using its molar mass (192.12&nbsp;g\/mol&nbsp;):<\/p>\n\n\n\n<p>Grams = Moles \u00d7 Molar Mass<br>Grams of H\u2083C\u2086H\u2085O\u2087 = 0.000607 mol \u00d7 192.12&nbsp;g\/mol&nbsp;= 0.1166 g<br>Rounding to three significant figures, based on the given values, the mass is 0.117 grams.<\/p>\n\n\n\n<p>For the second question, we find the concentration in milligrams per milliliter. First, convert the mass from grams to milligrams (0.117 g \u00d7 1000 mg\/g = 117 mg). Then, divide this mass by the original volume of the juice aliquot:<\/p>\n\n\n\n<p>Concentration = 117 mg \/ 15.0 mL = 7.80 mg\/mL<br>The result is reported to three significant figures.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/08\/learnexams-banner4-76.jpeg\" alt=\"\" class=\"wp-image-279795\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>The Correct Answer and Explanation is: Answer:The amount of citric acid in the aliquot is&nbsp;0.117 grams.The concentration of citric acid is&nbsp;7.80 mg per mL of juice. Explanation: This problem is solved using stoichiometry, which relates the quantities of reactants and products in a chemical reaction. The goal is to work from the known information about [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-279787","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/279787","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=279787"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/279787\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=279787"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=279787"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=279787"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}