An Instructor ‚ „ s Solutions Manual to Accompany STEEL DESIGN, 5th Edition By WILLIAM T. SEGUI Complete And Study material 596pages LEARNEXAMS

PREFACE This instructor's manual contains solutions to the problems in Chapters 1–10 of Steel Design, 5th Edition. Solutions are given for all problems in the Answers to Selected Problems section of the textbook, as well as most of the others. In general, intermediate results to be used in subsequent calculations were recorded to four significant figures, and final results were rounded to three significant figures. Students following these guidelines should be able to reproduce the numerical results given. However, the precision of the results could depend on the grouping of the computations and on whether intermediate values are retained in the calculator between steps. In many cases, there will be more than one acceptable solution to a design problem; therefore, the solutions given for design problems should be used only as a guide in grading homework. I would appreciate learning of any errors in the textbook or solutions manual that you may discover. You can contact me at [email protected]. A list of errors and corrections in the textbook will be maintained at http://www.ce.memphis.edu/segui/errata.html. William T. Segui August 15, 2011 CHAPTER 1 - INTRODUCTION 1.5-1 (a) P  2067  1340 lb f  P A  1340 19.7  68. 02 psi f  68.0 psi (b) Since E  f  ,   f E  68.02 29,000,000  2. 35  10−6   2.35  10−6 1.5-2 (a) L  9/sin45°  12. 73 ft ΔL  L  8.9  10−4  12.73  12  0.136 in. ΔL  0.136 in. (b) f  E  8.9  10−4  29,000  25. 81 ksi P  fA  25.811.31  33. 8 kips P  33.8 kips 1.5-3 (a) A  d2 4  0.52 4  0.1963 in.2 f  P A  5000 0.1963  25,470 psi   ΔL L  6.792  10−3 8  8. 49  10−4 E  f   25,470 8.49  10−4  3.0  107 psi E  30,000 ksi (b) Fu  Pu A  14,700 0.1963  74,900 psi Fu  74.9 ksi