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1. (TCO 8) 35.0 mL of 0.25 M NaOH is neutralized by 23.6 mL of an HCl solution. The molarity of the HCl solution is (show your work): (Points: 5)
molarity = moles solute/liters solution 0.25 M= moles NaOH/0.035 L moles NaOH=0.00875 moles NaOH
2. (TCO 1) How many mL are in 3.5 pints? Show your work. (Points: 5)
3.5 pints is equivalent to 1656.116
1 pint=473.176 mi 3.5 pints 473.176mL1656.116mL
3. (TCO 3) What is the name of the following compound: Zn,P.? (Points: 5)
It's Zinc Phosphide
4. (TCO 3) What is the name of the following compound: AgNO,? (Points: 5)
Silver nitrate
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