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Digital Logic Circuit Analysis and Design Second Edition Problem Solutions Manual

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Digital Logic Circuit
Analysis and Design
Second Edition
Problem Solutions Manual
Victor P. Nelson
Auburn University
Bill D. Carroll
University of Texas at Arlington
H. Troy Nagle
North Carolina State University
J. David Irwin
Auburn University
Contents
Chapter 1 Number Systems and Digital Codes .......................................... 1
Chapter 2 Logic Circuits and Boolean Algebra ......................................... 27
Chapter 3 Combinational Logic Circuit Design and Analysis................... 107
Chapter 4 Introduction to Sequential Circuits ....................................... 189
Chapter 5 Synchronous Sequential Circuit Analysis and Design............. 215
Chapter 6 Asynchronous Sequential Circuit Analysis and Design........... 265
Chapter 7 Programmable Digital Logic Devices ..................................... 303
Chapter 8 Design of Digital Systems...................................................... 347
© 2020 Pearson Education, Inc., Hoboken, NJ. All rights reserved. This material is protected under all copyright laws as they currently exist.
No portion of this material may be reproduced, in any form or by any means, without permission in writing from the publisher.
Chapter 1 – Number Systems and Digital Codes
1.1 Calculate + BA , − BA , × BA , and ÷ BA for the following pairs of binary numbers.
(a) 10101, 1011
1 1 1 1 1
1 0 1 0 1
+ 1 0 1 1
1 0 0 0 0 0
0 10 0 10
1 0 1 0 1
‒ 1 0 1 1
1 0 1 0
1 0 1 0 1
× 1 0 1 1
1 0 1 0 1
1 0 1 0 1
0 0 0 0 0
1 0 1 0 1
1 1 1 0 0 1 0 1
1
1 0 1 1 1 0 1 0 1
- 1 0 1 1
Remainder 1 0 1 0
(b) 1011010, 101111
1 1 1 1 1 1
1 0 1 1 0 1 0
+ 1 0 1 1 1 1
1 0 0 0 1 0 0 1
10 1 10
0 10 0 0 10 0 10
1 0 1 1 0 1 0
‒ 1 0 1 1 1 1
1 0 1 0 1 1
1 0 1 1 0 1 0
× 1 0 1 1 1 1
1 0 1 1 0 1 0
1 0 1 1 0 1 0
1 0 1 1 0 1 0
1 0 1 1 0 1 0
0 0 0 0 0 0 0
1 0 1 1 0 1 0
1 0 0 0 0 1 0 0 0 0 1 1 0
0 1 . 1 1
1 0 1 1 1 1 1 0 1 1 0 1 0 . 0 0
1 0 1 1 1 1
1 0 1 1 0 1 0
1 0 1 1 1 1
0 1 0 1 0 1 1 0
1 0 1 1 1 1
0 1 0 0 1 1 1 0
1 0 1 1 1 1
Remainder 0 1 1 1 1 1

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