FL 5 AAMC MCAT QUESTION WITH COMPLETE SOLUTION
Question : What quantity of Compound 1 must be
provided to prepare 100.00 mL of solution with a
concentration equal to Ki?
A. 48.4 mg
B. 24.2 mg
C. 5.64 mg
D. 2.92 mg
"Compound 1 (molar mass: 483.5 g/mol ) has been shown
to inhibit HIV-1 protease with Ki = 60.3 μM (Table 1). Ki
is the dissociation constant for the enzyme-bound
inhibitor, which is either EI or ESI, depending on the type
of inhibitor."
Correct answer: D
In 100.00 mL solution, 60.3 μM Compound 1 contains
6.03 μmol, which when converted to mol and multiplied
by the molar mass, yields 0.00292 g or 2.92 mg.
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