Online Instructor’s Solutions Manual to accompany Applied Mechanics for Engineering Technology Keith M. Walker (Complete And Verified Study material) (74pages) LEARNEXAMS

1-2 12 + 6x + 3 = 27 6X27-12-3 x= 2

1-3 28=X+X 4 12 = 14 x 12 28x12 = x

14

x=24

1-4 0x5 2x-2 10x+40 y = 100 -10x+6y-20 46480 11.74 y=

1-50x8 243 176 x + 24968 39x-24y=168 215X+0=1136 X = 5.28

1-6 x= +214-(4)(13)-8) (2(13) = +22 20.5 26 0.8650-0.712

1-7 (3x)x+(x) = 8(x) 3x²-8x+5=0 x=(-8)(-8)-(4)(3)(5) 6 x = +8 ± 164-60 6

x= 1.67 of 1

1-8 Q=35 opposite angle 6-180-35-90-55° C-180-555 125

1-9

4 = 80° oppolite angle 6180-80 = 1000 C100 opposite angle a=90-40=50° 1-10

R = 17 28.1

1-18 Lan 20= Ax 2.18 in

tan 40 = A tan 55= 20 A A=3.36 Fe A-14.

1-19 Sin-25 38.7

1-201 tan 65 y 4 y=8.58 mm

1-21 Sin = 33 72 27.30

1-221 C²-15+422-2(15)(42) Cos 120 C=51.2 cm

1-23 C:15²+252-2(15)(25) Cos 65 C= 23.1 Ft

1-24) (5.5)3+4-2(3)(4) cose 77.36 (2nd guadrant) or 102.6°

1-25 (CB)=55+90²-2(55) (30) cos25 CB 46.21m.

1-26 d² = 62+82-2(6)(8) Cos 130 d-12.7 m

1-27) (CD)²= (25)²+(4)-2(25)(4) Cos 16° CD-0.174 m

1-28 A Sin/20 50 Sin 20 A = 1271.

1-29 AC Sim 73 AD = sin65 640 Sin 42 Sin42 AC= 913 Fe AD 865 Ft 640

1-301

d

14

d=9.32 m

Sin40 SIM 105 Cose-It 48 1-31 73°