.png){kind=logo}
Instructions • Use black ink or ball-point pen. • Fill in the boxes at the top of this page with your name, centre number and candidate number. • Answer all questions. • Answer the questions in the spaces provided – there may be more space than you need. Information • The total mark for this paper is 90. • The marks for each question are shown in brackets – use this as a guide as to how much time to spend on each question. • For the question marked with an asterisk (*), marks will be awarded for your ability to structure your answer logically showing the points that you make are related or follow on from each other where appropriate. • A Periodic Table is printed on the back cover of this paper. Advice • Read each question carefully before you start to answer it. • Show all your working in calculations and include units where appropriate. • Check your answers if you have time at the end. Time 1 hour 45 minutes 9CH0/01 You must have: Scientific calculator, Data Booklet, ruler Chemistry Advanced PAPER 1: Advanced Inorganic and Physical Chemistry Pearson Edexcel Level 3 GCE *P67093RA0232* 2  Answer ALL questions. Some questions must be answered with a cross in a box . If you change your mind about an answer, put a line through the box and then mark your new answer with a cross . 1 This question is about atomic structure and the Periodic Table. (a) Complete the table to show the relative charges and masses for a neutron and an electron. (2) Particle Relative charge Relative mass proton +1 1 neutron electron (b) Atomic emission spectroscopy provides evidence for the existence of (1) A atoms B electrons C isotopes D quantum shells (c) Draw the shape of a p orbital. (1) *P67093RA0332* Turn over 3  (d) The melting temperatures of two elements in Period 3 are given in the table. Element silicon chlorine Melting temperature / K 1683 172 Explain, in terms of the structure and bonding of each element, the difference between these values. (3) .................................................................................................................................................................................................................................................................................... .................................................................................................................................................................................................................................................................................... .................................................................................................................................................................................................................................................................................... .................................................................................................................................................................................................................................................................................... .................................................................................................................................................................................................................................................................................... .................................................................................................................................................................................................................................................................................... .................................................................................................................................................................................................................................................................................... .................................................................................................................................................................................................................................................................................... .................................................................................................................................................................................................................................................................................... (Total for Question 1 = 7 marks) *P67093RA0432* 4  2 This question is about the elements in Group 2 of the Periodic Table. (a) Magnesium powder is added to a beaker of water containing a few drops of Universal Indicator. The apparatus is set up as shown and allowed to stand for a few days. test tube filled with water water and Universal Indicator filter funnel magnesium powder State two changes that will be seen after a few days. (2) .................................................................................................................................................................................................................................................................................... .................................................................................................................................................................................................................................................................................... .................................................................................................................................................................................................................................................................................... (b) Explain how the trend in the reactivity of the Group 2 elements is determined by their electronic configurations. (3) .................................................................................................................................................................................................................................................................................... .................................................................................................................................................................................................................................................................................... .................................................................................................................................................................................................................................................................................... .................................................................................................................................................................................................................................................................................... .................................................................................................................................................................................................................................................................................... .................................................................................................................................................................................................................................................................................... .................................................................................................................................................................................................................................................................................... .................................................................................................................................................................................................................................................................................... .................................................................................................................................................................................................................................................................................... .................................................................................................................................................................................................................................................................................... *P67093RA0532* Turn over 5  (c) Calcium reacts with chlorine. Ca(s) + Cl2(g) → CaCl2(s) Explain, in terms of electrons, why this is a redox reaction. (2) .................................................................................................................................................................................................................................................................................... .................................................................................................................................................................................................................................................................................... .................................................................................................................................................................................................................................................................................... .................................................................................................................................................................................................................................................................................... .................................................................................................................................................................................................................................................................................... .................................................................................................................................................................................................................................................................................... (d) An experiment was carried out to determine the molar volume of hydrogen at room temperature. 0.035g of magnesium was added to excess hydrochloric acid and 32cm3  of hydrogen was produced. Mg(s) + 2HCl(aq) → MgCl2(aq) + H2(g) Calculate the molar volume of hydrogen from the results of this experiment. Include units in your answer
.png)