Solution Manual For Basic Principles And Calculations In Chemical Engineering 9th Edition By David M Himmelblau Chapter-2-11 (Complete And Verified Study material) (502pages) LEARNEXAMS

Chapter 2 Solutions 2.1 Units of Measure 2.1.1 (a) N/mm or nm (nanometer) (b) °C/M/s (c) 100 kPa (d) 273.15 K (e) 1.50m, 45 kg (f) 250°C (g) J/s (h) 250 N 2.1.2 a. The device measures equivalent masses when it is balanced (both pans aligned horizontally). b. The compressed spring measures the force under the influence of gravity. If this system were applied on the surface of the moon, the measurement would be much smaller. 2.2 Unit Conversions 2.2.1 (a) 2.5 mi 1610 m 3 4.0 10 m or 4.0 km mi = × (b) 52.66 Btu 1.055 kJ 55.56 kJ Btu = (c) 5.00 hp 0.7457 kW 3.73 kW hp = (d) -3 3 50. gal 3.875 10 m min 3 3 -1 3.2 10 m s min gal 60 s × − = × (e) f 2 2 f 22.5 lb 6.958 kPa 157 kPa in lb /in = (f) m -1 m 45.6 slug 32.174 lb 0.4536 kg 665 kg s s slug lb = (g) 17.0 hp h 745.7 J 3600 s 6 3 4.56 10 J=4.56 10 kJ=4.56 MJ hp s h =× × (h) -3 3 2 3 -2 -1 2 2 2 35.9 gal 3.875 10 m ft 1.50 m m s s ft gal 0.3048 m × = (i) o o o o 816.67 R 9 R 5 K 357 F+459.67=816.67 R = 454 K