• wonderlic tests
  • EXAM REVIEW
  • NCCCO Examination
  • Summary
  • Class notes
  • QUESTIONS & ANSWERS
  • NCLEX EXAM
  • Exam (elaborations)
  • Study guide
  • Latest nclex materials
  • HESI EXAMS
  • EXAMS AND CERTIFICATIONS
  • HESI ENTRANCE EXAM
  • ATI EXAM
  • NR AND NUR Exams
  • Gizmos
  • PORTAGE LEARNING
  • Ihuman Case Study
  • LETRS
  • NURS EXAM
  • NSG Exam
  • Testbanks
  • Vsim
  • Latest WGU
  • AQA PAPERS AND MARK SCHEME
  • DMV
  • WGU EXAM
  • exam bundles
  • Study Material
  • Study Notes
  • Test Prep

1. The circuit is first tested with a computer design and simulation program, which can simulate

Testbanks Dec 29, 2025 ★★★★★ (5.0/5)
Loading...

Loading document viewer...

Page 0 of 0

Document Text

Electronics Fundamentals A Systems Approach

Thomas L. Floyd

David M. Buchla

Solution Manual For NOTE: (For Complete File, Download link at the end of this File) 1 / 4

2

  • The circuit is first tested with a computer design and simulation program, which can simulate
  • the performance and look for potential problems. When the simulation is satisfactory, a prototype circuit is constructed, tested, and modified as needed before putting it into production.

  • Semiconductor and component manufacturers as well as printed circuit board manufacturers.
  • Electronic assemblies have become more complex but also more reliable, so there is less need
  • for repair. It is generally cheaper for manufacturers to replace a board than troubleshoot it to the component level. Skills needed by technicians tend to be broader skills than in the past.

  • Electrical systems deal primarily with power; electronic systems involve signals and a logical
  • sequence of processes.

  • Advantages are that the digital signal can be processed and stored easily; it is also less subject
  • to noise.

  • A block diagram shows signal flow in a system; a flowchart shows a logical process.
  • (a) An electronic oscillator generates a repetitive electronic signal
  • (b) An oscillator does not have a signal input.

  • (a) High Voltage Direct Current

CHAPTER 1

SYSTEMS, QUANTITIES AND UNITS

SECTION 1-1 The Electronics Industry SECTION 1-2 Introduction to Electronic Systems SECTION 1-3 Types of Circuits 2 / 4

3 (b) HVDC is used for long distance and underwater power transmission.

  • A carrier is a high frequency radio wave that can be modulated (changed) by a lower
  • frequency signal.

  • A stair-step output; each step represents a different digital value.
  • (a) 3000 = 3  10
  • 3 (b) 75,000 = 7.5  10 4 (c) 2,000,000 = 2  10 6

  • (a) 500

1 = 0.002 = 2  10

3

(b) 2000

1 = 0.0005 = 5  10

4

(c) 000,000,5

1 = 0.0000002 = 2  10

7

  • (a) 8400 = 8.4  10
  • 3 (b) 99,000 = 9.9  10 4 (c) 0.2  10 6

= 2  10

5

  • (a) 0.0002 = 2  10
  • 4 (b) 0.6 = 6  10 1

(c) 7.8  10 2 (already in scientific notation)

  • (a) 2.5  10
  • 6 = 0.0000025 (b) 5.0  10 2 = 500 (c) 3.9  10 1

= 0.39

  • (a) 4.5  10
  • 6

= 0.0000045

(b) 8  10 9

= 0.000000008

(c) 4.0  10 12

= 0.0000000000040

  • (a) 9.2  10
  • 6

+ 3.4  10

7

= 9.2  10

6

+ 34  10

6

= 4.32  10

7

(b) 5  10 3

+ 8.5  10

1

= 5  10

3

+ 0.00085  10

3

= 5.00085  10

3

(c) 5.6  10 8

+ 4.6  10

9

= 56  10

9

+ 4.6  10

9

= 6.06  10

8

  • (a) 3.2  10
  • 12

 1.1  10

12

= 2.1  10

12

(b) 2.6  10 8

 1.3  10

7

= 26  10

7

 1.3  10

7

= 24.7  10

7

(c) 1.5  10 12

 8  10

13

= 15  10

13

 8  10

13

= 7  10

13

  • (a) (5  10
  • 3

)(4  10

5

) = 5  4  10

  • + 5

= 20  10

8

= 2  10

9

SECTION 1-4 Scientific and Engineering Notation 3 / 4

4

(b) (1.2  10 12

)(3  10

2

) = 1.2  3  10

12 + 2

= 3.6  10

14

(c) (2.2  10 9

)(7  10

6

) = 2.2  7  10

 9  6

= 15.4  10

15

= 1.54  10

14

  • (a) 2
  • 3 105.2 100.1 

 = 0.4  10

3  2

= 0.4  10

1 = 4

(b) 6 8

2.5 10

5.0 10

  

 = 0.5  10

6  (8)

= 0.5  10

2 = 50

(c) 5 8 102 102.4  

 = 2.1  10

8  (5)

= 2.1  10

13

  • (a) 89,000 = 89  10
  • 3

(b) 450,000 = 450  10 3

(c) 12,040,000,000,000 = 12.04  10 12

  • (a) 2.35  10
  • 5

= 235  10

3

(b) 7.32  10 7

= 73.2  10

6

(c) 1.333  10 9 (already in engineering notation)

  • (a) 0.000345 = 345  10
  • 6

(b) 0.025 = 25  10 3

(c) 0.00000000129 = 1.29  10 9

  • (a) 9.81  10
  • 3

= 9.81  10

3

(b) 4.82  10 4

= 482  10

6

(c) 4.38  10 7

= 438  10

9

  • (a) 2.5  10
  • 3

+ 4.6  10

3

= (2.5 + 4.6)  10

3

= 7.1  10

3

(b) 68  10 6

+ 33  10

6

= (68 + 33)  10

6

= 101  10

6

(c) 1.25  10 6

+ 250  10

3

= 1.25  10

6

+ 0.25  10

6

= (1.25 + 0.25)  10

6

= 1.50  10

6

  • (a) (32  10
  • 3

)(56  10

3

) = 1792  10

(3 + 3)

= 1792  10

= 1.792  10

3

(b) (1.2  10 6

)(1.2  10

6

) = 1.44  10

(6  6)

= 1.44  10

12

  • / 4

User Reviews

★★★★★ (5.0/5 based on 1 reviews)
Login to Review
S
Student
May 21, 2025
★★★★★

This document featured practical examples that helped me ace my presentation. Such an outstanding resource!

Download Document

Buy This Document

$1.00 One-time purchase
Buy Now
  • Full access to this document
  • Download anytime
  • No expiration

Document Information

Category: Testbanks
Added: Dec 29, 2025
Description:

Electronics Fundamentals A Systems Approach Thomas L. Floyd David M. Buchla Solution Manual For NOTE: (For Complete File, Download link at the end of this File) 1. The circuit is first tested with ...

Unlock Now
$ 1.00