• wonderlic tests
  • EXAM REVIEW
  • NCCCO Examination
  • Summary
  • Class notes
  • QUESTIONS & ANSWERS
  • NCLEX EXAM
  • Exam (elaborations)
  • Study guide
  • Latest nclex materials
  • HESI EXAMS
  • EXAMS AND CERTIFICATIONS
  • HESI ENTRANCE EXAM
  • ATI EXAM
  • NR AND NUR Exams
  • Gizmos
  • PORTAGE LEARNING
  • Ihuman Case Study
  • LETRS
  • NURS EXAM
  • NSG Exam
  • Testbanks
  • Vsim
  • Latest WGU
  • AQA PAPERS AND MARK SCHEME
  • DMV
  • WGU EXAM
  • exam bundles
  • Study Material
  • Study Notes
  • Test Prep

A First Book of ANSI C

Testbanks Dec 29, 2025
Loading...

Loading document viewer...

Page 0 of 0

Document Text

A First Book of ANSI C 4e Gary Bronson (Solutions Manual All Chapters, 100% Original Verified, A+ Grade) All Chapters Solutions Manual Supplement files download link at the end of this file. 1 / 4

A First Book of ANSI C, 4th Edition Solutions 1-1 A First Book of ANSI C, 4th Edition

14188-35560

Chapter 1 Solutions Exercises 1.1 Short Answer Questions 1.A bit is the smallest and most basic data item which is a switch that can be either opened or closed. A bit can represent the values 0 and 1.

2.A byte is a grouping of eight bits. A byte can assume 256 distinct patterns.

3.A byte uses a pattern of eight bits, such as 00110011, to represent characters in a computer.

4.A word is a single unit combination of one or more bytes. Word sizes for some

common computers include: a single byte for early personal computers, such as

the Apple IIe and Commodore machines; two bytes for the first IBM PCs; four bytes for the more current Intel-based PCs.

5.The two principal parts of the CPU are the Control Unit and the Arithmetic and Logic Unit (ALU). The Control Unit monitors the overall operation of the computer while the ALU performs all the arithmetic and logic functions provided by the system.

6.The main difference between RAM and ROM is RAM is volatile while ROM is nonvolatile. Both RAM and ROM are random access which means that every section of memory can be accessed randomly as quickly as any other section.

7.a. The input/output unit is the interface that provides access to and from the computer to which peripheral devices are attached.b.Three devices that would be connected to the input/output unit include keyboards, monitors and printers. (Please note there are other examples the student could include.) 8.Secondary storage is a permanent storage area for programs and data. Three examples of secondary storage include magnetic tapes, magnetic disks and CD- ROMS. (Please note there are other examples the student could include.) 2 / 4

A First Book of ANSI C, 4th Edition Solutions 1-2

  • The difference between sequential storage and direct access storage is sequential
  • storage allows data to be written or read in one sequential stream from beginning to end while direct access storages allows data to be written or read from any one file or program independent of its position on the storage medium. Direct access storage allows the computer to jump directly to the desired point in storage, rather than passing through all intervening points like sequential storage would require.In other words, the data can be accessed more quickly.

  • A microprocessor is a single microchip CPU. In everyday life microprocessors are
  • used in notebook and desktop computers, calculators, and even digital watches.(Please note there are other examples the student could include.)

Exercises 1.2

  • computer program – a self-contained set of instructions and data used to
  • operate a computer to produce a specific result

  • programming – the process of developing and writing a program
  • programming language –the set of data and instructions that can be used to
  • construct a program

  • high-level language – languages in which the instructions resemble human
  • languages, such as English, and can be run on a variety of computer types

  • low-level language – language that uses instructions that are directly tied to one
  • type of computer

  • machine language – a programming language consisting of the binary codes the
  • can be executed by a computer

  • assembly language – a programming language that uses symbolic names for
  • operations and memory addresses

  • procedure-oriented language – high-level language in which the instructions
  • are only used to create self-contained units referred to as procedures

  • object-oriented language – high-level language which defines and manipulates
  • objects to produce results

  • source program – program written in a computer language
  • compiler – program which translates high-level languages as a complete unit
  • before any individual statement is executed

  • assembler – a program that converts, or translates, assembly language programs
  • into machine language

  • A high-level language can be translated to run on a variety of computer types,
  • while a low-level language is directly tied to one type of computer.

  • Procedure-oriented languages create logically consistent sets of instructions, or
  • procedures, to produce a specific result while object-oriented languages create and manipulate objects to produce specific results.

  • / 4

A First Book of ANSI C, 4th Edition Solutions 1-3

  • An assembler translates assembly language programs, while both compilers and
  • interpreters translate high-level source programs. A compiler translates a high- level source programs as a complete unit before any one statement is actually executed, while an interpreter translates individual source program statements one at a time into executable statements. Each interpreted statement is executed immediately after translation.

  • Add the data in memory location 1 to the data in memory location 2.
  • Multiply the data in memory location 3 by the data in memory location 2.Subtract the data in memory location 4 from the data in memory location 3.Divide the data in memory location 3 by the data in memory location 5.

  • 3 + 5 = 8

6 * 3 = 18

6 – 14 = -8

6 / 4 = 1.5

5. ADD 1, 2

MUL 3, 2

SUB 4, 3

DIV 3, 5

6. (10 + 20) * .6 = 18

Exercises 1.3

  • Fix a flat tire
  • Stop vehicle in a safe, level location Set the parking brake Get jack, lug-wrench, and spare tire Check air pressure in spare tire Use jack to raise vehicle so that damaged tire is clear of ground Remove hubcap Use lug-wrench to loosen each individual lug nut Use lug-wrench to remove each individual lug nut Place lug nuts into hubcap Remove tire from axle Place spare tire onto axle Restore each lug nut, and tighten by hand Tighten all lug nuts securely with lug-wrench Replace hubcap

  • / 4

User Reviews

Login to Review

No reviews yet. Be the first to share your thoughts!

Download Document

Buy This Document

$1.00 One-time purchase
Buy Now
  • Full access to this document
  • Download anytime
  • No expiration

Document Information

Category: Testbanks
Added: Dec 29, 2025
Description:

A First Book of ANSI C 4e Gary Bronson (Solutions Manual All Chapters, 100% Original Verified, A+ Grade) All Chapters Solutions Manual Supplement files download link at the end of this file. A Firs...

Unlock Now
$ 1.00