A First Course in Differen�al Equa�ons with Modeling Applica�ons 10e Dennis Zill (Test Bank All Chapters, 100% Original Verified, A+ Grade) 1 / 4
Chapter 01 Form C: INTRODUCTION TO DIFFERENTIAL EQUATIONS
MULTIPLE CHOICE
- The differential equation is
Select the correct answer.
- first order linear
- second order linear
- third order linear
- first order nonlinear
- second order nonlinear
ANS: B PTS: 1
- The differential equation is
Select the correct answer.
- first order linear
- second order linear
- third order linear
- first order nonlinear
- second order nonlinear
ANS: E PTS: 1
- The differential equation is
Select the correct answer.
- first order linear
- second order linear
- third order linear
- first order nonlinear
- second order nonlinear
ANS: A PTS: 1
- The differential equation is
Select the correct answer.
- first order linear
- second order linear
- third order linear
- first order nonlinear
- second order nonlinear
ANS: E PTS: 1
- The differential equation is 2 / 4
Select the correct answer.
- first order linear
- second order linear
- third order linear
- first order nonlinear
- second order nonlinear
ANS: C PTS: 1
- The values of m for which is a solution of are
Select the correct answer.
- 2 and 4
- and
- 3 and 4
- 2 and 3
- 1 and 5
ANS: D PTS: 1
- The values of m for which is a solution of are
Select the correct answer.
- 2 and 4
- and
- 3 and 5
- 2 and 3
- 1 and 5
ANS: A PTS: 1
- The values of c for which is a constant solution of are
Select the correct answer.
- 1 and 4
- and
- 1 and
- and 3
- 1 and 3
ANS: C PTS: 1
- The values of m for which is a solution of are
Select the correct answer.
- 1 and 4
- and 4
- 2 and 3
- and 3 / 4
- and 5
ANS: E PTS: 1
- The population of a town increases at a rate proportional to its population. Its initial
population is 1000. The correct initial value problem for the population, , as a function of time, t, is Select the correct answer.
a.
b.
c.
d.
e.
ANS: A PTS: 1
- The solution of the initial value problem is , where
Select the correct answer.
- 2
- 3
- 1
b.
d.
ANS: A PTS: 1
- The solution of the initial value problem is ,
where Select the correct answer.
- 2
b.c.d.
- 1
ANS: B PTS: 1
- The initial value problem has a unique solution guaranteed by
- / 4
Theorem 1.1 if Select the correct answer.