Copyright 2018 McGraw-Hill Higher Education. Permission required for reproduction or display. All rights reserved.

Copyright ©2018 McGraw-Hill Higher Education. Permission required for reproduction or display. All rights reserved.

1. Convert the following to engineering notation:

(a) 0.045 W = 45 mW

(b) 2000 pJ= 2 nJ

(c) 0.1 ns = 100 ps

(d) 39,212 as = 3.9212×10 4 ×10 -18

= 39.212×10

-15 s = 39.212 fs

(e) 3 Ω

(f) 18,000 m = 18 km

(g) 2,500,000,000,000 bits = 2.5 terabits

(h) 3 15 2 21 3 3 10 atoms 10 cm 10 atoms/m cm 1 m

  

=  

   (it’s unclear what a “zeta atom” is)

=45´10

-3

W =2000´10

-12

=2´10

-9 J

=0.1´10

-9

=100´10

-12 s =18´10 3 m

=2.5´10

12 bits Chapter 2 (Engineering Circuit Analysis , 9e William Hayt, Steven Durbin, Jamie Phillips) (Solution Manaul, For Complete File, Download link at the end of this File) (There is no Solution Manual for Chapter 1) 1 / 4

Engineering Circuit Analysis 9 th Edition Chapter Two Exercise Solutions

Copyright ©2018 McGraw-Hill Higher Education. Permission required for reproduction or display. All rights reserved.

2. Convert the following to engineering notation:

(a) 1230 fs = 1.23 ps

(b) 0.0001 decimeter = 10 m

(c) 1400 mK

(d) 32 nm = 32 nm

(e) 13,560 kHz = 13.56 MHz

(f) 2021 micromoles = 2.021 millimoles

(g) 13 deciliters

(h) 1 hectometer

=1.2310

3 ´10 -15

=1.23´10

-12 s =1´10 -4 ´10 -1

=10´10

-6 m

=1.4´10

3 ´10 -3

=1.4 K =32´10

-9 m

=1.356´10

4 ´10 3

=13.56´10

6 Hz

=2.021´10

3 ´10 -6

=2.021´10

-3 moles

=13´10

-1 =1.3 liters =100 meters 2 / 4

Engineering Circuit Analysis 9 th Edition Chapter Two Exercise Solutions

Copyright ©2018 McGraw-Hill Higher Education. Permission required for reproduction or display. All rights reserved.

3. Express the following in engineering units:

(a) 1212 mV = 1.121 V

(b) 10 11 pA = 10 11 ×10 -12 = 100 mA

(c) 1000 yoctoseconds = 1 zs

(d) 33.9997 zeptoseconds

(e) 13,100 attoseconds 15 1.31 10 s = 1.31 fs − =

(f) 10 −14 zettasecond=10 -14 ×10 21 =10 7

=10×10

6 s = 10 Ms

(g) 10 −5 second = 10 s

(h) 10 −9 Gs

=1´10

3 ´10 -24

=1´10

-21 seconds =10´10 -6 seconds =10 -9 ´10 9 =1 second 3 / 4

Engineering Circuit Analysis 9 th Edition Chapter Two Exercise Solutions

Copyright ©2018 McGraw-Hill Higher Education. Permission required for reproduction or display. All rights reserved.

4. Expand the following distances in simple meters:

(a) 1 Zm (b) 1 Em (c) 1 Pm (d) 1 Tm (e) 1 Gm (f) 1 Mm

=1´10

21 m =1´10 18 m =1´10 15 m =1´10 12 m =1´10 9 m =1´10 6 m

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