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1.1
FUNDAMENTALS OF POLYMER
ENGINEERING
A.Kumar & Rakesh Gupta Solution of Problems of Chapter 1 to 15 1 / 4
1.2
CHAPTER 1
P1.1 OH OH OH
CH2 - CH - CH2 and C6H4C(O) – OC(O)
(A) (B)
‘A’ has a functionality of 3 owing to the presence of three –OH groups which may react with the comonomer. In case of ‘B’, the phthalic anhydride can break into (O)C – C6H4 – C(O) - and it’s functionality is 2. Therefore, BA BBAA NN f.Nf.N f + + = 32
)2*3()3*2(
+ + = = 2.4 P1.2 Ethylene glycol being bi-functional will give straight chain portion. Therefore in its presence the cross-linking density is reduced.
P1.3 2 / 4
1.3
P1.4
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1.4
P1.5 P = Polyethylene chain which may be branched for LDPE and linear M monomer for HDPE
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