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INSTRUCTOR'S SOLUTIONS MANUAL
TO ACCOMPANY
Fundamentals of Logic Design Enhanced Seventh Edition
CHARLES H. ROTH, JR.
LARRY L. KINNEY
EUGENE B. JOHN 1 / 3
TABLE OF CONTENTS
I. INTRODUCTION 1
1.1 Using the Text in a Lecture Course 1 1.2 Some Remarks About the Text 2 1.3 Using the Text in a Self-Paced Course 2 1.4 Use of Computer Software 4 1.5 Suggested Equipment for Laboratory Exercises 5
II.SOLUTIONS TO HOMEWORK PROBLEMS 7
Unit 1 Problem Solutions 7 Unit 2 Problem Solutions 17 Unit 3 Problem Solutions 23 Unit 4 Problem Solutions 31 Unit 5 Problem Solutions 41 Unit 6 Problem Solutions 57 Unit 7 Problem Solutions 71 Unit 8 Problem Solutions 91 Unit 9 Problem Solutions 97 Unit 10 Problem Solutions 113 Unit 11 Problem Solutions 119 Unit 12 Problem Solutions 125 Unit 13 Problem Solutions 145 Unit 14 Problem Solutions 157 Unit 15 Problem Solutions 177 Unit 16 Problem Solutions 201 Unit 17 Problem Solutions 215 Unit 18 Problem Solutions 229 Unit 19 Problem Solutions 245 Unit 20 Problem Solutions 257
III. SOLUTIONS TO DESIGN, SIMULATION,
AND LAB EXERCISES 263
Unit 8 Design Problems 263 Unit 10 Design and Simulation Problems 283 Unit 12 Design and Simulation Problems 297 Unit 16 Design and Simulation Problems 303 Unit 17 Simulation and Lab Problems 313 Unit 20 Lab Design Problems 321
IV. SAMPLE UNIT TESTS 351 2 / 3
Unit 1 Solutions 7 © 2021 Cengage. All Rights Reserved. May not be scanned, copied or duplicated, or posted to a publicly accessible website, in whole or in part.
II.SOLUTIONS TO HOMEWORK PROBLEMS
Unit 1 Problem Solutions
757.25
10
16 | 757 0.25
16 | 47 r5 16 16 | 2 r15=F 16
(4).00
- r2
∴757.25
10
= 2F5.40
16
= 0010 1111 0101.0100 0000
2
2 F 5 4 0
1.1 (a)123.17 10
16 | 123 0.17
16 | 7 r11 16
- r7 (2).72
16
(11).52
16
(8).32
∴123.17
10
= 7B.2B
16
= 0111 1011.0010 1011
2
7 B 2 B
356.89
10
16 | 356 0.89
16 | 22 r4 16 16 | 1 r6 (14).24
- r1 16
(3).84
16
(13).44
16
(7).04
∴356.89
10
= 164.E3
16
= 0001 0110 0100.1110 0011
2
1 6 4 E 3
1.1 (c)
1063.5
10
16 | 1063 0.5
16 | 66 r7 16 16 | 4 r2 (8).00
- r4
∴1063.5
10
= 427.8
16
= 0100 0010 0111 .1000
2
4 2 7 8
EB1.6 16
= E × 16
2
+ B × 16
1
+ 1 × 16
+ 6 × 16
–1
= 14 × 256 + 11 × 16 + 1 + 6/16 = 3761.375
10
1110 1011 0001.011(0)
2
E B 1 6
7261.3
8
= 7 × 8
3
+ 2 × 8
2
+ 6 × 8
1
+ 1 + 3 × 8
–1
= 7 × 512 + 2 × 64 + 6 × 8 + 1 + 3/8 = 3761.375
10
111 010 110 001.011
8
7 2 6 1 3
1.2 (a)59D.C 16
= 5 × 16
2
+ 9 × 16
1
+ D × 16
+ C × 16
–1
= 5 × 256 + 9 × 16 + 13 + 12/16 =
1437.75
10
0101 1001 1101.1100
16
5 9 D C
2635.6
8
= 2 × 8
3
+ 6 × 8
2
+ 3 × 8
1
+ 5 × 8
+ 6 × 8
–1
= 2 × 512 + 6 × 64 + 3 × 8 + 5 + 6/8 =
1437.75
10
010 110 011 101.110
8
2 6 3 5 6
1.1 (b) 1.1 (d) 1.2 (b)
3BA.25
14
= 3 × 14
2
+ 11 × 14
1
+ 10 × 14
+ 2 × 14
–1
+ 5 ×14
–2
= 588 + 154 + 10 + 0.1684 = 752.1684
10
6 | 752 0.1684
- | 125 r2 6
- | 20 r5 (1).0104
- | 3 r2 6
- r3 (0).0624
6
(0).3744
6
(2).2464
6
(1).4784
∴3BA.25
14
= 752.1684
10
= 3252.1002
6 1.3
1457.11
10
16 | 1457 0.11
16 | 91 r1 16 16 | 5 r11=B 16
(1).76
- r5 16
(12).16
∴1457.11
10
= 5B1.1C
16
5B1.1C
16
= 11 23 01.01 30
4
5 B 1 1 C
5 B 1 1 C
5B1.1C
16
= 010110110001.00011100
2
=2661.070
8
2 6 6 1 0 7 0
DEC.A 16
= D × 16
2
+ E × 16
1
+ C × 16
+ A× 16
–1
= 3328 + 224 + 12 + 0.625 =3564.625
10 1.4 (b) 1.4 (c) 1.4 (d)
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