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Operator Grade 3 Practice Examination

Class notes Jan 2, 2026 ★★★★☆ (4.0/5)
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Vermont Wastewater Treatment Facility Operator Grade 3 Practice Examination Questions And Correct Answers (Verified Answers) Plus Rationales 2026 Q&A | Instant Download Pdf

  • What is the primary purpose of secondary treatment in a municipal
  • wastewater plant?

  • Remove grit
  • Settle heavy inorganic solids
  • Reduce organic matter through biological processes
  • Disinfect effluent

Rationale: Secondary treatment relies on microorganisms to remove BOD

and suspended biological solids.

  • What does BOD primarily measure?
  • Chemical corrosion potential
  • Oxygen demand from biodegradable organics 1 / 4
  • Toxicity of effluent
  • Chlorine residual

Rationale: BOD reflects the oxygen required by microbes to break down

organic material.

  • Typical DO concentration maintained in an activated sludge aeration

tank is:

  • 0.5 mg/L
  • 2.0 mg/L
  • 6.0 mg/L
  • 10 mg/L

Rationale: Around 2 mg/L supports aerobic microbial activity efficiently.

  • What microorganism is most important in nitrification?
  • Protozoa
  • Fungi
  • Nitrifying bacteria
  • Viruses

Rationale: Nitrifiers (e.g., Nitrosomonas, Nitrobacter) oxidize ammonia to

nitrate.

5. Sludge bulking is commonly caused by:

  • Excess alkalinity
  • Overgrowth of filamentous organisms
  • Improper chlorination 2 / 4
  • Low influent flow

Rationale: Filaments interfere with settling, creating fluffy sludge.

  • What does F/M ratio compare?
  • Food to modulus
  • Filaments to microorganisms
  • Organics applied to biomass present
  • Flow to membrane

Rationale: F/M = influent organics relative to biological mass in aeration.

  • What is the optimal pH for nitrification?

A. 4.0–5.0

B. 5.5–6.5

C. 7.5–8.5

D. 9.0–10.0

Rationale: Nitrifiers thrive in mildly alkaline conditions.

  • Which test measures settleability of activated sludge?

A. BOD

B. TSS

C. SVI

D. COD

Rationale: Sludge Volume Index indicates settling characteristics.

9. The main purpose of grit removal is to: 3 / 4

  • Destroy pathogens
  • Protect downstream equipment
  • Remove organics
  • Improve sludge digestion

Rationale: Grit causes abrasion and wear.

  • What is the typical chlorine contact time for disinfection?
  • 1–3 minutes
  • 5–8 minutes
  • 15–30 minutes
  • 60–120 minutes

Rationale: Adequate CT ensures pathogen inactivation.

  • What does TSS measure?
  • Dissolved solids
  • Organic acids
  • Suspended solids that can be filtered
  • Chlorine demand

Rationale: TSS captures particulate solids in wastewater.

12. A clarifier with rising solids may indicate:

  • Excess alkalinity
  • Hydraulic overload
  • Proper sludge removal
  • / 4

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Added: Jan 2, 2026
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